The correct increasing order of ionic character of the following molecule is:
LiF, K2O, N2, SO2, ClF3
1. N2 < SO2 < ClF3 < K2O < LiF
2. N2 > SO2 > ClF3 > K2O < LiF
3. N2 > SO2 > K2O > ClF3 > LiF
4. LiF > K2O < ClF3 > SO2 > N2
From the perspective of molecular orbital theory, which statement is false?
1. | is not a stable molecule. |
2. | is not stable but is expected to exist. |
3. | Bond strength of is maximum amongst the homonuclear diatomic molecules belonging to the second period. |
4. | The order of energies of molecular orbitals in molecule is:
|
The decreasing order of ionic character of the N-H, F-H, C-H, and O-H, is :
1. | N-H > F-H > C-H > O-H |
2. | F-H > N-H > C-H > O-H |
3. | O-H > C-H > F-H > N-H |
4. | F-H > O-H > N-H > C-H |
The number of (i) sp2 hybridized carbon atoms and (ii) bonds are present in the following compound are:
1. 7, 5
2. 8, 6
3. 7, 6
4. 8, 5
In , formal charge on every oxygen atom and P-O bond order respectively are:
1. -0.75 and 1.25
2. -0.5 and 2
3. 1 and 1.5
4. -0.75 and 2
In a regular octahedral molecule, MX6, the number of X–M–X bonds at 180º is:
1. | Two | 2. | Six |
3. | Four | 4. | Three |
In NO3– ion, the number of bond pair and lone pair of electrons on nitrogen atom are respectively:
1. | 2, 2 | 2. | 3, 1 |
3. | 1, 3 | 4. | 4, 0 |
The incorrect statements among the following are-
(a) | NaCl being an ionic compound is a good conductor of electricity in the solid-state |
(b) | In canonical structure, there is a difference in the arrangement of atoms |
(c) | Hybrid orbitals form stronger bonds than pure orbitals |
(d) | VSEPR theory can explain the square planar geometry of XeF4 |
1. | (a) and (b) only | 2. | (b) and (c) only |
3. | (c) and (d) only | 4. | (b) and (d) only |
Combination of atoms A and B that forms an anti-bonding molecular orbital is :
1.
2.
3.
4.
Match List - I with List - II
List - I | List - II | ||
(a) | (i) | Square pyramidal | |
(b) | (ii) | Trigonal planar | |
(c) | (iii) | Octahedral | |
(d) | (iv) | Trigonal bipyramidal |
Choose the correct answer from the options given below:
(a) | (b) | (c) | (d) | |
1. | (iii) | (i) | (iv) | (ii) |
2. | (iv) | (iii) | (ii) | (i) |
3. | (iv) | (iii) | (i) | (ii) |
4. | (ii) | (iii) | (iv) | (i) |