Ncert Exercises & Solutions

Q. 8. In an experiment, DNA is treated with the compound which tends to place itself amongst the stacks of nitrogenous base pairs. As a result of this, the distance between two consecutive base increases. From 0.34-0.44 nm calculate the length of DNA double helix (which has $2 \times 10^{9}$ bp) in the presence of saturating of this compound.

The length of DNA double helix =

2 \times 10^{9} \times 0.44 \times 10^{- 9} / bp .

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