Ncert Exercises & Solutions

8.13 How will you ‘weigh the sun’, that is estimate its mass? The mean orbital radius of the earth around the sun is 1.5 × 108 km.

$H e r e,$
$r = 1.5 \times 10^{8} k m = 1.5 \times 10^{11} m$
$T = 1 y e a r = 365.25 d a y s = 365.25 \times 24 \times 60 \times 60 s .$
$G = 6.67 \times 10^{- 11} N m^{2} k g^{- 2}$
$W e h a v e,$
$M = \frac{4 π^{2} r^{3}}{G T^{2}}$
$= \frac{4 \times {(3.14)}^{2} \times {(1.5 \times 10^{11})}^{3}}{6.67 \times 10^{- 11} \times {(365.25 \times 24 \times 60 \times 60)}^{2}}$
$= 2 \times 10^{30} k g .$

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