A wire is suspended from the ceiling and stretched under the action of a weight \(F\) suspended from its other end. The force exerted by the ceiling on it is equal and opposite to the weight.

(a) Tensile stress at any cross-section \(A\) of the wire is \(F/A.\)
(b) Tensile stress at any cross-section is zero.
(c) Tensile stress at any cross-section \(A\) of the wire is \(2F/A.\)
(d) Tension at any cross-section \(A\) of the wire is \(F.\)

 
The correct statements are:

1. (a), (b) 2. (a), (d)
3. (b), (c) 4. (a), (c)
(2) Hint: The tension remains the same throughout the length of the wire.
Step 1:  Find the force in the wire.
As shown in the diagram, clearly, the force at each cross-section is F.
Step 2: Find the stress developed in the wire.
Now applying the formula,
Stress=TensionArea=FA
Tension=Applied force=F