Ncert Exercises & Solutions

A wire is suspended from the ceiling and stretched under the action of a weight \(F\) suspended from its other end. The force exerted by the ceiling on it is equal and opposite to the weight.

(a)	Tensile stress at any cross-section \(A\) of the wire is \(F/A.\)
(b)	Tensile stress at any cross-section is zero.
(c)	Tensile stress at any cross-section \(A\) of the wire is \(2F/A.\)
(d)	Tension at any cross-section \(A\) of the wire is \(F.\)

Choose the correct option from the given ones:
1. (a) and (b) only
2. (a) and (d) only
3. (b) and (c) only
4. (a) and (c) only

Hint: The tension remains the same throughout the length of the wire.

Step: Find the stress developed in the wire.

As shown in the diagram, clearly, the force at each cross-section is \(F.\)

The stress developed in the wire is given by;
\( \text { Stress }=\frac{\text { Tension }}{\text { Area }}=\frac{F}{A} \)
The tension developed in the wire is given by;
\(\Rightarrow \text {Tension }=\text { Applied force }=F\)
Hence, option (2) is the correct answer.

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