The supply frequency and the natural frequency are equal at resonance condition in the circuit.

Given Resistance of the resistor, R = 20 Ω

Given Inductance of the inductor, L = 1.5 H

Given Capacitance of the capacitor , C = 35 μF = 30 × 10 ^{– 6} F

An AC source with a voltage of V = 200 V is connected to the LCR circuit,

We know that the Impedance of the above combination can be calculated by the following relation,

$aZ=\sqrt{R^2+(X_L-X_C{)}^2}$

At resonant condition in the circuit , X _L = X _C

Therefore , Z = R = 20 Ω

We know that Current in the network is given by the relation :

$\text{ à }I=\frac{V}{Z}=\frac{200}{20}=10A$

Therefore, the average power that is being transferred to the circuit in one full cycle:

                                 V I = 200 x 10 = 2000 W