7.24 At a hydroelectric power plant, the water pressure head is at a height of 300 m and the water flow available is 100 m3s–1. If the turbine generator efficiency is 60%, estimate the electric power available from the plant (g = 9.8 ms–2).
Given,
Height of water pressure head, ℎ = 300 m
The volume of water flown in 1 sec, V = 100 m3
Mass of water, m = 100 × 103 = 105 kg
Efficiency, 𝑒 = 60%
The potential energy of water during one second = 𝑚𝑚𝑚𝑚ℎ = 105 × 9.8 × 300 =29.4 × 107 J s−1
Efficiency,
𝑒 = output power/input power
output power = 𝑒𝑒 × input power = 0.6 × 294 × 106 = 176 MW
Hence, 176 MW of power is available from the plant.
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