Ncert Exercises & Solutions

9.13: A small telescope has an objective lens of focal length 144 cm and an eyepiece of focal length 6.0 cm. What is the magnifying power of the telescope? What is the separation between the objective and the eyepiece?

Hint:

m = \frac{f_{\circ}}{f_{e}}

Step 1: Find the magnifying power of the telescope.
The focal length of the objective lens, = 144 cm
The focal length of the eyepiece, = 6.0 cm
The magnifying power of the telescope,

Step 2: Find the separation between the objective lens and the eyepiece.
The separation between the objective lens and the eyepiece = $f_{\circ} + f_{e} = 144 + 6 = 150 c m$

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