Ncert Exercises & Solutions

220 V

$220~\text{V}$ AC supply is connected between points

A

$A$ and

B

$B$ (figure). What will be the potential difference

V

$V$ across the capacitor?

1.	$220~\text{V}$	2.	$110~\text{V}$
3.	$0~\text{V}$	4.	$220\sqrt{2}~\text{V}$

(d) Hint: The p-n junction is forward biased for half-cycle.

Step 1: Find the potential difference across the capacitor.

As the p-n junction conducts during the positive half-cycle only, the diode-connected here will work in the positive half-cycle. The potential difference across C = peak voltage of the given AC voltage

= V_{0} = V_{rms} \sqrt{2} = 220 \sqrt{2} V .

$= V_{0} = V_{rms} \sqrt{2} = 220 \sqrt{2} V .$

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