A \(220~\text{V}\) AC supply is connected between points \(A\) and \(B\) (figure). What will be the potential difference \(V\) across the capacitor?

               

1. \(220~\text{V}\) 2. \(110~\text{V}\)
3. \(0~\text{V}\) 4. \(220\sqrt{2}~\text{V}\)
(d) Hint: The p-n junction is forward biased for half-cycle.
Step 1: Find the potential difference across the capacitor.
As the p-n junction conducts during the positive half-cycle only, the diode-connected here will work in the positive half-cycle. The potential difference across C = peak voltage of the given AC voltage=V0=Vrms2=2202 V.