Ncert Exercises & Solutions

A truth table for the given circuit is:

Hint: The output depends on the logic of the circuit.

Step: Find the truth table for the circuit.
Here,

C = A . B

$C=A.B$ and

D = \bar{A} . B

$D=\bar A.B$

E = C + D = (A . B) + (\bar{A} . B)

$E=C+D=(A.B)+(\bar A. B)$

The truth table of this arrangement of gates can be given by;

Hence, option (3) is the correct answer.