Ncert Exercises & Solutions

The amplifiers X, Y and Z are connected in series. If the voltage gains of X, Y and Z are 10, 20 and 30, respectively and the input signal is 1 mV peak value, then what is the output signal voltage (peak value)

(i) if DC supply voltage is 10 V?

(ii) if DC supply voltage is 5 V?

Hint: The output signal voltage depends on the voltage application.

Step 1: Find the voltage amplification.

Given,

A_{v_{x}} = 10, A_{v_{y}} = 20, A_{v_{z}} = 30;

∆ V_{i} = 1 mV = 10^{- 3} V

Now,

\frac{Output Signal Voltage (∆ V_{o})}{Input Signal Voltage (∆ V_{i})} = Total voltage amplification

\Rightarrow \frac{∆ V_{o}}{∆ V_{i}} = A_{v_{x}} \times A_{v_{y}} \times A_{v_{z}}

∆ V_{o} = A_{v_{x}} \times A_{v_{y}} \times A_{v_{z}} \times ∆ V_{i}

= 10 \times 20 \times 30 \times 10^{- 3} = 6 V

Step 2: Find the output voltage.

(i) If DC supply voltage is 10 V, then output is 6 V since theoretical gain is equal to practical gain, i.e., the output can never be greater than 6 V.

(ii) If DC supply voltage is 5 V, i.e., V_cc = 5 V. Then, the output peak will not exceed 5 V. Hence V_o = 5 V.

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