1.34 Suppose that the particle in Exercise in 1.33 is an electron projected with velocity vx = 2.0 × 106 m s–1. If E between the plates separated by 0.5 cm is 9.1 × 102 N/C, where will the electron strike the upper plate? (|e|=1.6 × 10–19 C, me = 9.1 × 10–31 kg.)
Velocity of the particle, vx=2.0×106m/s
Separation of the two plates, d = 0.5 cm=0.005 m
Electric field between the two plates, E = 9.1 x 102 N/C
Charge on an electron, q=1.6×10−19C
Mass of an electron, me = 9.1×10−31kg
Let the electron strike the upper plate at the end of plate L, when deflection is s. Therefore,
s=qEL22mV2x⇒L=√2smV2xqE=√2×0.005×9.1×10−311.6×10−19×9.1×102=√0.00025=0.016m=1.6cm
Therefore, the electron will strike the upper plate after traveling at 1.6 cm.
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