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A cricket ball of mass 150 g has an initial velocity u=(3ˆi+4ˆj)ms1 and a  final velocity v=(3ˆi+4ˆj)ms1, after being hit. The change in momentum (final momentum-initial momentum) is (in kgm/s)
1. zero
2. (0.45ˆi+0.6ˆj)
3. (0.9ˆi+1.2ˆj)
4. 5(ˆi+ˆj)

(c) Hint: The direction of the velocity changes.
Step 1: Find the change in momentum of the ball.
 Given, u=(3ˆi+4ˆj)m/s and v=(3ˆi+4ˆj)m/s
Mass of the ball = 150 g = 0.15 kg
p = Change in momentum
                     = Final momentum - Initial momentum                      =mvmu                     =m(vu)=(0.15)[(3ˆi+4ˆj)(3ˆi+4ˆj]]                     =(0.15)[6ˆi8ˆj]                     =[0.15×6ˆi+0.15×8ˆj]                     =[0.9ˆi+1.20ˆj]Hence,   Δp=[0.9ˆi+1.2ˆj]