Ncert Exercises & Solutions

3.5 A jet airplane travelling at the speed of 500 km h^–1 ejects its products of combustion at the speed of 1500 km h^–1 relative to the jet plane. What is the speed of the latter with respect to an observer on the ground ?

speed of the jet airplane, $v_{j e t}$ = 500 km/h

Relative speed of its products of combustion with respect to the plane,

$v_{s m o k e} = - 1500 k m / h r$

Speed of its products of combustion with respect to the ground = $v'_{s m o k e}$

Relative speed of its products of combustion with respect to the airplane,

$v_{s m o k e} = v'_{s m o k e} - v_{j e t}$
$\Rightarrow - 1500 = v'_{s m o k e} - 500$
$\Rightarrow v'_{s m o k e} = - 1000 k m / h r$
The negative sign indicates that the direction of its products of combustion is opposite to the direction of motion of the jet airplane.

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