The reactant which is entirely consumed in reaction is known as limiting reagent. In the reaction 2A+4B3C+4D, when 5 moles of A react with 6 moles of B, then

1. which is the limiting reagent?

2. calculate the amount of C formed.

2A+4B3C+4D
According to the given reaction, 2 moles of A react with 4 moles of B.
Hence, 5 moles of A will react with 10 moles of B (5×42=10 moles)
(a) It indicates that reactant B is limiting reagent as it will consume first in the reaction because we have only 6 moles of B.
(b) Limiting reagent decide the amount of product produced.
According to the reaction,
4 moles of B produces 3 moles of C
 6 moles of B will produce 3×64=4.5 moles of C.