3.15 Energy of an electron in the ground state of the hydrogen atom is
–2.18
×10–18J. Calculate the ionization enthalpy of atomic hydrogen in terms of
J mol
-1.

Hint: Apply the idea of mole concept to derive the answer.

The energy of an electron in the ground state of the hydrogen atom is –2.18 × 10-18 J.

Therefore, the energy required to remove that electron from the ground state of hydrogen

atom is 2.18 × 10-18 J.

Ionization enthalpy of atomic hydrogen = 2.18 × 10-18 J

Hence, ionization enthalpy of atomic hydrogen in terms of J mol–1

= 2.18 × 10-18 × 6.02 × 1023 J mol-1

 = 1.31 × 106

J mol-1