Ncert Exercises & Solutions

Species have same bond order are

1. $N_{2}$

2. $N_{2}^{-}$

3. $F_{2}^{+}$

4. $O_{2}^{-}$

(c, d)

Bond order of the following species are calculated using molecular orbital electronic configuration and found as

N_{2} = 3,

N_{2}^{-} = 2.5,

F_{2}^{+} = 1.5,

O_{2}^{-} = 1.5