Percentage of carbon in organic compound = 69 %
That is, 100 g of organic compound contains 69 g of carbon.
0.2 g of organic compound will contain $=\frac{69\times 0.2}{100}=0.138 of C$
Molecular mass of carbon dioxide, CO${}_2$ = 44 g
That is, 12 g of carbon is contained in 44 g of CO${}_2$.
Therefore, 0.138 g of carbon will be contained in $\frac{44\times 0.138}{12}$ = 0.506 g of CO${}_2$
Thus, 0.506 g of CO${}_2$ will be produced on complete combustion of 0.2 g of organic
compound.
Percentage of hydrogen in organic compound is 4.8.
i.e., 100 g of organic compound contains 4.8 g of hydrogen.
Therefore, 0.2 g of organic compound will contain $\frac{4.8\times 0.2}{100}=0.0096 g of H$
It is known that molecular mass of water (H${}_2$O) is 18 g.
Thus, 2 g of hydrogen is contained in 18 g of water. $\frac{18\times 0.0096}{2}=0.0864 g$
0.0096 g of hydrogen will be contained in of water
Thus, 0.0864 g of water will be produced on complete combustion of 0.2 g of the organic
compound.