Ncert Exercises & Solutions

What are hybridisation states of each carbon atom in the following compounds?

CH $_{2}$ =C=O, CH $_{3}$ CH=CH $_{2}$ , (CH $_{3}$ ) $_{2}$ CO, CH $_{2}$ =CHCN, C $_{6}$ H $_{6}$

(i)

\overset{l}{C} H_{2} = \overset{2}{C} = 0

C–1 is sp

^{2}

hybridised.

C–2 is sp

^{2}

hybridised.

(ii)

\overset{l}{C} H_{3} - \overset{2}{C} H = \overset{3}{C} H_{2}

C–1 is sp

^{3}

hybridised.

C–2 is sp

^{2}

hybridised.

C–3 is sp

^{2}

hybridised.

(iii)

O

| |

\underset{|}{C} H_{3} — \underset{2}{C} — \underset{3}{C} H_{3}

C–1 and C–3 are sp

^{3}

hybridised.

C–2 is sp

^{2}

hybridised.

(iv)

\overset{|}{C} H_{2} = \overset{2}{C} H - \overset{3}{C} \equiv N

C–1 is sp

^{2}

hybridised.

C–2 is sp

^{2}

hybridised.

C–3 is sp hybridised.

(v) C

_{6}

_{6}

All the 6 carbon atoms in benzene are sp

^{2}

hybridised.