Ncert Exercises & Solutions

Consider figure from the above question and answer the questions (i) to (vi) given below.

1. Redraw the diagram to show the direction of electron flow.

2. Is silver plate the anode or cathode?

3. What will happen if salt bridge is removed?

4. When will the cell stop functioning?

5. How will concentration of Zn²⁺ ions and Ag⁺ ions be affected when the cell functions?

6. How will the concentration of Zn²⁺ ions and Ag⁺ions be affected after the cell becomes ‘dead’?

(i) Electrons move from Zn fo Aq as E⁰ more negative for Zn, so Zn undergoes oxidation and Ag⁺ undergoes reduction.

(ii) Ag is the cathode as it is the site of reduction where Ag⁺ takos cloctrons from medium and deposit at cathode.

(iii) Cell will stop functioning because cell potential drops to zero. Al E = 0 reaction reaches equilibrium.

(iv) When E_cell = 0 because at this condition reaction reaches to equilibrium.

(v) Concentration of Zn²⁺ ions will increase and concentration of Ag⁺ ions will decrease because Zn is converted into Zn²⁺ and Ag⁺ is converted into Ag.

(vi) When E_cell = 0 equilibrium is reached and concentration of Zn²⁺ ions and Ag⁺ will not change.

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