A lamp emits monochromatic green light uniformly in all directions. The lamp is \(3\%\) efficient in converting electrical power to electromagnetic waves and consumes \(100\) W of power. The amplitude of the electric field associated with the electromagnetic radiation at a distance of \(5\) m from the lamp will be:
1. \(1.34\) V/m
2. \(2.68\) V/m
3. \(4.02\) V/m
4. \(5.36\) V/m

A parallel plate capacitor consists of two circular plates each of radius 2 cm, separated by a distance of 0.1 mm. If the voltage across the plates is varying at the rate of $5\times {10}^{13}$ V/s, then the value of displacement current is :

(1) 5.50 A

(2) $5.56\times {10}^2 A$

(3) 5.56$\times {10}^3$ A

(4) $2.28\times {10}^4 A$

In an electromagnetic wave, the direction of the magnetic field induction $\overrightarrow{B}$ is

(1) parallel to electric field $\overrightarrow{E}$

(2) perpendicular to electric field $\overrightarrow{E}$

(3) antiparallel to Poynting vector $\overrightarrow{S}$

(4) random

In an electromagnetic wave

(1) Power is transmitted along the magnetic field

(2) Power is transmitted along the electric field

(3) Power is equally transferred along with the electric and magnetic fields

(4) power is transmitted in a direction perpendicular to both the fields

For any E.M. wave if E = 100 V/m and the magnetising field is equal to 0.265 A/m. Then the rate of maximum energy flow per unit area is:

(1) $3.33\times {10}^{-5} J/m^2$

(2) 26.5 W/$m^2$

(3) $3\times {10}^8 J/m^2$

(4) None of these

A variable frequency AC source is connected to a capacitor. Then on increasing the frequency:

Source of an electromagnetic wave is

(1) A charge moving with constant velocity

(2) A charge at rest

(3) A charge moving in a circular orbit

(4) Charges cannot produce an EM wave

The dimension of E/H is that of 

(1) Impedance

(2) Inductance

(3) capacitance

(4) Inductance$\times$Capacitance

Poynting vector $\overrightarrow{P}$ for an EM wave is :

1. $\overrightarrow{P}=\overrightarrow{E}\times \overrightarrow{B}$

2. $\overrightarrow{P}=\overrightarrow{E}\times \overrightarrow{H}$

3. $\overrightarrow{P}=\frac{\overrightarrow{E}}{\overrightarrow{B}}$

4. $\overrightarrow{P}=\frac{\overrightarrow{E}}{\overrightarrow{H}}$

Which one statement is incorrect about the electromagnetic waves?

(1) $\overrightarrow{E}\times \overrightarrow{B}$ gives always the direction of propagation

(2) $\overrightarrow{E}$ is always perpendicular to $\overrightarrow{B}$

(3) Transverse in nature

(4) $\overrightarrow{E}$ is always parallel to $\overrightarrow{B}$