The major product obtained when ${\mathrm{Br}}_2/\mathrm{Fe}$ is reacted with 

${\mathrm{CH}}_3\mathrm{MgBr}+$$\stackrel{{\mathrm{H}}_3{\mathrm{O}}^{+}}{\to }A\stackrel{HBr}{\to }B\stackrel{Mg/ether}{\to }C\underset{H_3{O}^{+}}{\overset{HCHO}{\to }}D$ is

Identify X in the following sequence of reactions :

\(\mathrm{X} \xrightarrow[\text { (ii) } \mathrm{H}^{+} / \mathrm{H}_2 \mathrm{O}]{\text { (i) } \mathrm{CH}_3 \mathrm{MgX}} \mathrm{C}_5 \mathrm{H}_{12} \mathrm{O} \xrightarrow[573 \mathrm{~K}]{\mathrm{Cu}} \mathrm{C}_5 \mathrm{H}_{10}\)$\mathrm{}$

The reaction that does not yield benzoic acid as the major product is:
 

1. $\stackrel{{\mathrm{K}}_2{\mathrm{Cr}}_2{\mathrm{O}}_7}{\to }$

2. $\underset{\left(\mathrm{ii}\right){\mathrm{H}}_3{\mathrm{O}}^{+}}{\overset{\left(\mathrm{i}\right)\mathrm{NaOCl}}{\to }}$

3. $\stackrel{\mathrm{PCC}}{\to }$

4. $\stackrel{{\mathrm{KMnO}}_4/{\mathrm{H}}^{+}}{\to }$

Which of the following will not form a yellow precipitate on heating with an alkaline solution of iodine?

1. CH₃CH(OH)CH₃                                 

2. CH₃CH₂CH(OH)CH₃

3. CH₃OH                                               

4. CH₃CH₂OH

On warming with I₂ and aqueous NaOH, iodoform and sodium succinate are formed. The formula of the compound should be-

1. CH₃COCH₂CH₂CH₃
2. CH₃COC₆H₅
3. CH₃COCH₂CH₂COCH₃
4. None of the above

$\stackrel{\mathrm{PCC}}{\to }$$A \underset{{\mathrm{H}}^{+}}{\overset{{\mathrm{CH}}_3{\mathrm{NH}}_2}{\to }} B$$\stackrel{{\mathrm{H}}_2/\mathrm{Pd}-\mathrm{C}}{\to }$Product

Product is

1.

2.

3.

4.

$\stackrel{\mathrm{dilute} {\mathrm{OH}}^{-}}{\to }?$

The major product formed would be

The correct order of increasing reactivity towards
acid hydrolysis is
$\underset{\left(1\right)}{{\mathrm{CH}}_3{\mathrm{COOC}}_2{\mathrm{H}}_5} \underset{\left(2\right)}{C{H}_{3}COCl } \underset{\left(3\right)}{C{H}_{3}CONHC{H}_3}$

1. 1 < 2 < 3

2. 3 < 1 < 2

3. 1 < 3 < 2

4. 2 < 1 < 3

I.    R₁ = H             II R₁ = CH₃

      R₂ = CH₃             R₂ = -CH(CH₃)₂

III. R₁ = CH₃          IV R₁ = CH₃

      R₂ = CH₃              R₂ = C₂H₅

The rate of addition follows the order

1. I > II > III > IV

2. I > III > IV > II

3. I > III > II > IV

4. I > II > IV > III