Carboxylic acids have higher boiling points than aldehydes, ketones and even alcohols of comparable molecular mass. It is due to their

1. Formation of intramolecular H-bonding

2. Formation of carboxylate ion

3. More extensive association of carboxylic acid via van der waals force of attraction

4. Formation of intermolecular H-bonding

Consider the reactions: 
 
Identify A, X, Y and Z

1. A- Methoxymethane, X-Ethanol, Y-Ethanoic acid, Z-Semicarbazide.

2. A- Ethanal, X-Ethanol, Y-But-2-enal, Z-Semicarbazide.

3. A- Ethanol, X-Acetaldehyde, Y-Butanone, Z-Hydrazone.

4. A- Methoxymethane, X-Ethanoic acid, Y-Acetate, Z-Hydrazine.

Which of the following reactions is appropriate for converting acetamide to methanamine?

1. Hoffmann hypobromamide reaction

2. Stephens reaction

3. Gabriels phthalimide synthesis

4. Carbylamine reaction

$\underset{\left(1\right)}{\overset{\mathrm{HCl}}{\to }}\underset{\left(2\right)}{\overset{B{r}_2/Fe}{\to }}\underset{\left(3\right)}{\overset{H^{+}}{\to }}$

The major product is

1.
2.
3.
4.

CH₂=CH-CHO+HCN$\to$A(Major),

the compound 'A' is

1. CH₂=CH-CH-CH(OH)(CN)

2. CH₃-CH(CN)-CHO

3. CH₂(CN)-CH₂-CHO

4. CH₃-C(OH)(CN)-CH₃

The slowest step of Cannizarro's reaction is

1. Attack of nucleophilic

2. Hydride shift

3. Formation of anion

4. Transfer of proton

+Br₂ $\underset{∆}{\overset{{\mathrm{CCl}}_4}{\to }}$?

1.

2.

3.

4.

 $\underset{{\mathrm{H}}_3\mathrm{O}+}{\overset{{\mathrm{CH}}_3\mathrm{MgBr}\left(\mathrm{excess}\right)}{\to }}$Product,

Product is:-

1.

2.

3.

4.

The structure of the product is:

1.		2.
3.		4.