Hex-3-ene$\underset{2. \mathrm{Zn}, {\mathrm{H}}_2\mathrm{O}}{\overset{1. {\mathrm{O}}_3}{\to }}$ A $\underset{{\mathrm{H}}^{+}}{\overset{{\mathrm{KMnO}}_4}{\to }}$ B $\underset{\mathrm{Red} \mathrm{P}}{\overset{{\mathrm{Br}}_2}{\to }}$ C$\stackrel{\mathrm{KOH} \left(\mathrm{aq}\right)}{\to }$D

D is :-

1. ${\mathrm{CH}}_3-\underset{\mathrm{Br}}{\underset{|}{\mathrm{CH}}}-\mathrm{COOH}$                           

2.  ${\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{CHO}$

3. ${\mathrm{CH}}_3-\underset{\mathrm{Br}}{\underset{|}{\mathrm{CH}}}-\mathrm{CHO}$                         

4.  ${\mathrm{CH}}_3-\underset{OH}{\underset{|}{\mathrm{CH}}}-\mathrm{COOH}$

The reaction

is fastest when X is-

1. Cl

2. NH₂

3. OC₂H₅

4. OCOR

$\underset{\left(\mathrm{ii}\right){\mathrm{H}}^{+}/{\mathrm{H}}_2\mathrm{O}}{\overset{\left(\mathrm{i}\right)\mathrm{NaOH}/100°\mathrm{c}}{\to }}$

Major Product is:

1. 

2.

3.

4.

X $\underset{∆}{\overset{{\mathrm{KMnO}}_4}{\leftarrow }}$$\stackrel{∆}{\to }$Y

In the above reaction, X and Y are:

1. Identical

2. Homologes

3. Structural Isomers

4. Stereoisomers

The compound  can be exclusively oxidized into by

1. NaCN followed by hydrolysis

2. NaOI followed by H₃O⁺

3. Hot KMnO₄ followed by hydrolysis

4. K₂Cr₂O₇ followed by H₃O⁺

Phenolphthalein is produced on heating phthalic anhydride and conc. sulphuric acid with

1. Salicylic acid

2. Phenol

3. Phenacetin

4. Phenanthrene

A mixture of benzaldehyde and formaldehyde on heating with aqueous (conc.)NaOH solution gives

1. Benzyl alcohol and sodium formate

2. Sodium benzoate and methyl alcohol

3. Sodium benzoate and sodium formate

4. None of the above

Ethyl acetate on reaction with excess of methyl magnesium chloride and dil. H₂SO₄ gives-

1. Dimethyl ketone

2. Iso-propyl alcohol

3. Ethyl aceto acetate

4. t-Butyl alcohol

Cyanohydrin of 'X' gives lactic acid on hydrolysis. The compound 'X' will be:

1. Acetone                                 

2. Acetaldehyde

3. Propanal                                 

4. HCHO

Oxalic acid on treatment with conc. H₂SO₄ gives:

1. CO + H₂O₂                           

2.  H₂O +CO+CO₂

3. HCOOH + CO₂                       

4.  HCOOH + CO₂ +O₂