Q. No.Oxalic acid on treatment with conc. H2SO4 gives:
1. CO + H2O2
2. H2O +CO+CO2
3. HCOOH + CO2
4. HCOOH + CO2 +O2
Aldehydes and ketones will not form crystalline derivatives with
1. Sodium bisulphite
2. Phenyl hydrazine
3. Semicarbazide hydrochloride
4. Dihydrogen sodium phosphate
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Which one of the following compounds on treatment with LiAlH4 will give a product that will give a positive iodoform test?
1. CH3CH2CHO
2. CH3CH2COOCH3
3. CH3CH2OCH2CH3
4. CH3COCH3
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In this reaction,
\(CH_{3}CHO \ + \ HCN \ \xrightarrow[]{} \ CH_{3}CH(OH)CN \ \xrightarrow[]{\textbf{H.OH}} \\ CH_{3}CH(OH)COOH\)
an asymmetric compound is generated. The acid obtained would be:
1. 50% D + 50% L-isomer
2. 20% D + 80% L-isomer
3. D-isomer
4. L-isomer
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Which of the following has most acidic hydrogen?
1. 3-hexanone
2. 2,4-hexanedione
3. 2,5-hexanedione
4. 2,3-hexanedione
Acetaldehyde reacts with
1. Only electrophiles
2. Only nucleophiles
3. Only free radicals
4. Both electrophiles and nucleophiles
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Which compounds will not reduce Fehling's solution?
1. Methanal
2. Ethanal
3. Trichloroethanal
4. Benzaldehyde
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Fehling's solution is:
1. Acidified copper sulphate solution
2. Ammoniacal cuprous chloride solution
3. Copper sulphate, Rochelle salt + NaOH
4. None of the above
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Benzaldehyde and acetaldehyde can be distinguished by:
1. Iodoform test
2. 2:4 DNP test
3. reaction
4. Wolff-Kishner's reduction
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The conversion of CH3OH to CH3COOH can be brought in by:
1. K2Cr2O7/H+
2. CO + Rh
3. KMnO4
4. H3PO4
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