Compound (A) C₅H₁₀O forms a phenyl hydrazone and gives negative Tollen's and iodoform tests. Also, compound (A) on reduction gives n-pentane. Compound (A) is-

1.	A primary alcohol	2.	An aldehyde
3.	A ketone	4.	A secondary alcohol

Formaldehyde can be distinguished from acetaldehyde by:

1. Fehling's solution                     

2. Schiff's reagent

3. Ammonia                               

4. Ammoniacal ${\mathrm{AgNO}}_3$

What is the chemical reaction of lachrymator or tear gas?

1. C₆H₅COCl                               

2. C₆H₅OC₆H₅

3. C₆H₅COCH₂Cl                         

4. C₆H₅COCH₃

HCHO and HCOOH are distinguished by treating with:

1. Tollens reagent

2. NaHCO₃

3. Fehling's Solution

4. Benedict Solution

A compound that gives two different alcohols on reduction with ${\mathrm{LiAlH}}_4$ is:

1. ${\mathrm{CH}}_3{\mathrm{COOCH}}_3$                         

2. ${\mathrm{CH}}_3{\mathrm{COOC}}_2{\mathrm{H}}_5$

3. ${\mathrm{CH}}_3{\mathrm{COCH}}_3$                           

4. ${\mathrm{CH}}_3\mathrm{CHO}$

The compound formed when malonic acid heated with urea, is-                 

1. Cinnamic acid

2. Butyric acid

3. Barbituric acid

4. Crotonic acid

An ester is boiled with KOH. The product is cooled and acidified with conc. HCl. A white crystalline acid separates. The ester is-

1. Methyl acetate                       

2. Ethyl acetate

3. Ethyl formate                         

4. Ethyl benzoate

 A and B in the following reactions are $\mathrm{R}-\underset{\mathrm{O}}{\underset{\left|\right|}{\mathrm{C}}}-\mathrm{R}\text{'}$$\underset{\mathrm{KCN}}{\overset{\mathrm{HCN}/}{\to }}$A$\stackrel{\mathrm{B}}{\to }$

1. A=${\mathrm{RR}}^{\text{'}}{\mathrm{CH}}_2\mathrm{CN}$, B=NaOH

2. A=, B=${\mathrm{CH}}_3$

3. A=, B=${\mathrm{CH}}_3$

4. A=, B=${\mathrm{LiAlH}}_4$

Consider the following transformations

CH₃COOH $\stackrel{{\mathrm{CaCO}}_3}{\to }$A$\stackrel{\mathrm{heat}}{\to }$B$\underset{\mathrm{NaOH}}{\overset{{\mathrm{I}}_2}{\to }}$C The molecular formula of C is                       

1. ${\mathrm{CH}}_3-\underset{\mathrm{I}}{\overset{\mathrm{OH}}{\underset{\left|}{\overset{\right|}{\mathrm{C}}}}}-{\mathrm{CH}}_3$

2. ${\mathrm{ICH}}_2-{\mathrm{COCH}}_3$

3. ${\mathrm{CHI}}_3$

4. ${\mathrm{CH}}_3\mathrm{I}$

Benzoic acid gives benzene on being heated with X and phenol gives benzene on being heated with Y. Therefore, X and Y are respectively                                                     

1. Sodalime and Copper

2. Zn dust and NaOH

3. Cu and sodalime

4. Sodalime and zinc dust