Q. No.
Aniline in a set of the following reactions yielded a coloured product 'Y'.
The structure of 'Y' would be
1. 
2. 
3. 
4. 
The structure of 'Y' would be
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2. 1, 4– Dinitrobenzene
3. 1, 2, 4– Trinitobenzene
4. 1, 2– Dinitrobenzene
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+ 
is :
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2. Azoxybenzene
3. Azobenzene
4. Aniline
Method by which aniline cannot be prepared is
1. Hydrolysis phenyl isocyanide with acidic solution
2. Degradation of benzamide with bromine in alkaline Solution
3. Reduction of nitrobenzene with H/Pd in ethanol
4. Potassium salt of phthalimide treated with chlorobenzene followed by the hydrolysis aqueous NaOH solution
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| 1. | Arylamines are generally more basic than alkylamines because the nitrogen lone-pair electrons are not delocalized by interaction with the aromatic ring -electron system |
| 2. | Arylamines are generally more basic than alkylamines because of aryl group |
| 3. | Arylamines are generally more basic than alkylamines, because the nitrogen atom in arylamines is sp-hybridlzed |
| 4. | Arylamines are generally less basic than alkylamines because the nitrogen lone-pair electrons are delocalized by interaction with the aromatic ring -electron system. |
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A given nitrogen-containing aromatic compound A reacts with Sn/HCl, followed by HNO2 to give an unstable compound B. B, on treatment with phenol, forms a beautiful coloured compound C with the molecular formula C12H10N2O . The structure of compound A is-
1.
2.
3.
4.
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