Six similar bulbs are connected as shown in the figure with a DC source of emf E and zero internal resistance.

The ratio of power consumption by the bulbs when (i) all are glowing and (ii) in the situation when two from section A and one from section B are glowing, will be:

1. 2: 1

2. 4: 9

3. 9: 4

4. 1: 2

Subtopic:  Combination of Resistors | Heating Effects of Current |
 60%
From NCERT
NEET - 2019
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In a discharge tube ionization of enclosed gas is produced due to collisions between:

1. positive ions and neutral atoms/molecules

2. negative electrons and neutral atoms/molecules

3. photons and neutral atoms/molecules

4. neutral gas atoms/molecules

Subtopic:  Energy Band theory |
 55%
From NCERT
AIPMT - 2006
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A cell can be balanced against 100 cm and 110 cm of potentiometer wire, respectively with and without being short-circuited through a resistance of 10 Ω. lts internal resistance is :

1.  1.0 Ω

2.  0.5 Ω

3.  2.0 Ω

4.  zero

Subtopic:  Grouping of Cells |
 54%
From NCERT
AIPMT - 2008
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See the electrical circuit shown in this figure. Which of the following equations is a correct equation for it? 

1. ε1-(i1+i2)R-i1r1=0
2. ε2-i2r2-ε1-i1r1=0
3. -ε2-(i1+i2)R+i2r2=0
4. ε1-(i1+i2)R+i1r1=0
Subtopic:  Kirchoff's Voltage Law |
 63%
AIPMT - 2009

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The internal resistance of a 2.1 V cell which gives a current of 0.2 A through a resistance of 10 Ω is :
1. 0.5Ω
2. 0.8Ω
3. 1.0Ω
4. 0.2Ω
Subtopic:  EMF & Terminal Voltage |
 66%
From NCERT
AIPMT - 2013

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In the circuit shown cells, \(A\) and \(B\) have negligible resistance. For \(V_A =12 ~\text{V}\), \(R_1 = 500 ~\Omega \), and \(R = 100 ~\Omega \) the galvanometer \((\text{G}) \) shows no deflection. The value of \(V_B\) is: 
     

1. \(4\) V
2. \(2\) V
3. \(12\) V
4. \(6\) V

Subtopic:  Kirchoff's Voltage Law |
 57%
From NCERT
AIPMT - 2012

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A wire of resistance 4Ω is stretched to twice its original length. The resistance of stretched wire would be :
1. 4Ω
2. 8Ω
3. 16Ω
4. 2Ω
Subtopic:  Derivation of Ohm's Law | Combination of Resistors |
 75%
From NCERT
AIPMT - 2013

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A potentiometer wire of length L and a resistance r are connected in series with a battery of e.m.f. E0and resistance r1. An unknown e.m.f. is balanced at a length l of the potentiometer wire. The e.m.f. E will be given by :

1. LE 0rlr1

2. E0r(r+r1)·lL

3. E0lL

4. LE0r(r+r1)1

 68%
From NCERT
NEET - 2015

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The resistance of a wire is \('R'~\text{ohm}.\) If it is melted and stretched \('n'\) times its original length, its new resistance will be:-
1. \(\frac{R}{n}\)
2. \(n^2 R\)
3. \(\frac{R}{n^2}\)
4. \(nR\)

Subtopic:  Derivation of Ohm's Law |
 81%
From NCERT
NEET - 2017

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A filament bulb (500 W, 100 V) is to be used in a 230 V main supply. When a resistance R is connected in series, it works perfectly and the bulb consumes 500 W. The value of R is :

1.  230 Ω

2.  46 Ω

3.  26 Ω

4.  13 Ω

Subtopic:  Heating Effects of Current |
 63%
NEET - 2016

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