In the circuit shown in the figure, the current through :

(1) The 3Ω resistor is 0.50A

(2) The 3Ω resistor is 0.25 A

(3) The 4Ω resistor is 0.50A

(4) The 4Ω resistor is 0.25 A

I-V characteristic of a copper wire of length L and area of cross-section A is shown in figure. The slope of the curve becomes :

(1) More if the experiment is performed at higher temperature

(2) More if a wire of steel of same dimension is used

(3) More if the length of the wire is increased

(4) Less if the length of the wire is increased

The potential difference across the 100Ω resistance in the following circuit is measured by a voltmeter of 900 Ω resistance. The percentage error made in reading the potential difference is :

(1) $\frac{10}{9}$

(2) 0.1

(3) 1.0

(4) 10.0

You are given several identical resistances each of value R = 10 Ω and each capable of carrying maximum current of 1 ampere. It is required to make a suitable combination of these resistances to produce a resistance of 5 Ω which can carry a current of 4 amperes. The minimum number of resistances of the type R that will be required for this job 

(1) 4

(2) 10

(3) 8

(4) 20

Following figure shows cross-sections through three long conductors of the same length and material, with square cross-section of edge lengths as shown. Conductor B will fit snugly within conductor A, and conductor C will fit snugly within conductor B. Relationship between their end to end resistance is

(1) R_A = R_B = R_C

(2) R_A > R_B > R_C

(3) R_A < R_B < R

(4) Information is not sufficient

A ring is made of a wire having a resistane 

${\mathrm{R}}_0=12\mathrm{\Omega }$. Find the points A and B, as shown

in the figure, at which a current carrying 

conductor should be connected so that the 

resistance R of the sub circuit between these

points is equal to 8/3$\mathrm{\Omega }$

1. $\frac{{\mathrm{l}}_1}{{\mathrm{l}}_2}=\frac{5}{8}$                    2. $\frac{{\mathrm{l}}_1}{{\mathrm{l}}_2}=\frac{1}{3}$

3. $\frac{{\mathrm{l}}_1}{{\mathrm{l}}_2}=\frac{3}{8}$                    4. $\frac{{\mathrm{l}}_1}{{\mathrm{l}}_2}=\frac{1}{2}$

In the given circuit, the potential of the point E is 

(1) Zero

(2) –8 V

(3) –4/3 V

(4) 4/3 V

A battery of internal resistance 4Ω is connected to the network of resistances as shown. In order to give the maximum power to the network, the value of R (in Ω) should be :

(1) 4/9

(2) 8/9

(3) 2

(4) 18

When the key K is pressed at time t = 0, which of the following statement about the current I in the resistor AB of the given circuit is true?
          

In the circuit shown below, the cell has an e.m.f. of 10 V and internal resistance of 1 ohm. The other resistances are shown in the figure. The potential difference $V_A-V_B$ is :

(1) 6 V

(2) 4 V

(3) 2 V

(4) –2 V