Q. No.A circuit when connected to an AC source of 12 V gives a current of 0.2 A. The same circuit when connected to a DC source of 12 V, gives a current of 0.4 A. The circuit is:
(1) series LR
(2) series RC
(3) series LC
(4) series LCR
The core of a transformer is laminated because:
| 1. | Energy losses due to eddy currents may be minimized |
| 2. | The weight of the transformer may be reduced |
| 3. | Rusting of the core may be prevented |
| 4. | Ratio of voltage in primary and secondary may be increased |
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An AC voltage is applied to a resistance R and an inductor L in series. If R and the inductive reactance are both equal to 3, the phase difference between the applied voltage and the current in the circuit is:
1.
2.
3. zero
4.
In the given circuit the reading of voltmeter V1 and V2 are 300 V each. The reading to the voltmeter V3 and ammeter A are respectively:
1. 150 V, 2.2 A
2. 220 V, 2.2 A
3. 220 V, 2.0 A
4. 100 V, 2.0 A
An inductor 20 mH, a capacitor 100 μF, and a resistor 50 are connected in series across a source of emf, V= 10sin314t. The power loss in the circuit is:
1. 0.79 W
2. 0.43 W
3. 2.74 W
4. 1.13 W
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The potential differences across the resistance, capacitance and inductance are 80 V, 40 V and 100 V respectively in an L-C-R circuit. The power factor of this circuit is:
1. 0.4
2. 0.5
3. 0.8
4. 1.0
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2. 0.76 W
3. 0.89 W
4. 0.51 W
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3. current l(t) leads voltage V(t) by 180°
4. current l(t), lags voltage V(t) by 90o
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| 1. | \(\frac{\varepsilon^{2} R}{\left[R^{2}+\left(L \omega-\frac{1}{C \omega}\right)^{2}\right]}\) | 2. | \(\frac{\varepsilon^{2} \sqrt{R^{2}+\left(L \omega-\frac{1}{C \omega}\right)^{2}}}{R}\) |
| 3. | \(\frac{\varepsilon^{2}\left[R^{2}+\left(L \omega-\frac{1}{C \omega}\right)^{2}\right]}{R}\) | 4. | \(\frac{\varepsilon^{2}R}{\sqrt{R^{2}+\left(L \omega-\frac{1}{C \omega}\right)^{2}}}\) |
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2. a capacitance of reactance XC = XL is included in the same circuit
3. an iron rod is inserted in the coil
4. frequency of the AC source is decreased
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