The fringe width in a Young's double-slit experiment can be increased. If we decrease:

1. Width of the slits

2. Separation of the slits

3. The wavelength of the light used

4. Distance between slits and screen

In a YDSE, the central bright fringe can be identified.

1. as it has a greater intensity than the other bright fringes

2. as it is wider than the other bright fringes

3. as it is narrower than the other bright fringes

4. by using white light instead of single-wavelength light

If Young's double-slit experiment is performed with white light, then which of the following is not true?

1. the central maximum will be white

2. there will not be a completely dark fringe

3. the fringe next to the central will be red

4. the fringe next to the central will be violet

In Young's double-slit experiment, the interference pattern is observed on the screen L distance apart from slits, the average distance between adjacent fringes is x and slits separation is d, then the wavelength of light will be:

1. xd/L

2. xL/d

3. Ld/x

4. Ldx

Light of wavelength $\lambda$ in air enters a medium of refractive index $\mu$. Two points in this medium, lying along the path of this light, are at a distance x apart. The phase difference between these points is:

1. $\frac{2\mathrm{\pi \mu x}}{\lambda }$

2. $\frac{2\mathrm{\pi x}}{\mu \lambda }$

3. $\frac{2\mathrm{\pi }(\mathrm{\mu }-1)\mathrm{x}}{\lambda }$

4. $\frac{2\mathrm{\pi x}}{(\mu -1)\lambda }$

The ratio of the intensity at the centre of a bright fringe to the intensity at a point one-quarter of the fringe width from the centre is:

1. 2

2. 1/2

3. 4

4. 16

In Young's double-slit interference experiment, if the slit separation is made threefold, the fringe width becomes:

1. sixfold

2. threefold

3. 3/6 fold

4. 1/3 fold

In Young's interference experiment, if the slits are of unequal width, then:

1. no fringes will be formed

2. the positions of minimum intensity will not be completely dark

3. bright fringe as displaced from the original central position

4. distance between two consecutive dark fringes will not be equal to the distance between two consecutive bright fringes

Two beams of light having intensities I and 4I interfere to produce a fringe pattern on a screen. The phase between the beams is $\mathrm{\pi }/2$ at point A and $\mathrm{\pi }$ at point B. Then, the difference between the resultant intensities at A and B is:

1. 2I

2. 4I

3. 5I

4. 7I

Two coherent light sources P and Q each of wavelength $\lambda$ are separated by a distance 3$\lambda$. The maximum number of minima formed on line AB, which runs from $-\infty to +\infty$, is

1. 2

2. 4

3. 6

4. 8