Pick out the incorrect statement

1. Equivalent conductance increases with dilution

2. Molar conductance increases with dilution

3. Specific conductance increases with dilution

4. Specific resistance increases with dilution

When NaCl solution is electrolysed using Pt electrodes then pH of solution

1. Increases

2. Decreases

3. Remains same

4. Firstly increases and then decreases

By how much will the potential of half cell Cu²⁺| Cu change if the solution is diluted to 100 times at 298 K. It will -

What will be the molar conductance at infinite dilution for NH₄OH. If at infinite dilution the molar conductances of Ba(OH)₂, BaCl₂ and NH₄Cl are 523.28, 280.0 and 129.8 ohm^-1 cm^-1 mol^-1 respectively.
1. 502.88
2. 373.68
3. 251.44
3. 226.96

At 25$°$C the specific conductance of sturated solution of AgCl is 2.3 X 10-6 ohm^-1cm^-1. What will be the solubility of AgCl at 25$°$C if ionic conductances of ${\mathrm{Ag}}^{\oplus }$ and ${\mathrm{Cl}}^{⊝}$ at infinite dilution are 61.9 and 76.3 ohm^-1cm²mol^-1 respectively.

1. 1.66 X 10^-11M

2. 3.18 X 10^-6M

3. 6.01 X 10^-5M

4. 1.66 X 10^-5M

$2{\stackrel{\oplus }{\mathrm{Ag}}}_{\left(\mathrm{aq}\right)} + {\mathrm{Cu}}_{\left(\mathrm{s}\right)} \stackrel{ }{\rightleftharpoons } {{\mathrm{Cu}}_{\left(\mathrm{aq}\right)}}^{+2} + 2{\mathrm{Ag}}_{\left(\mathrm{s}\right)}$

The cell potential for this reaction is 0.46V. Which of the following change will increase the potential the most ?

(1) $\left[\stackrel{\oplus }{\mathrm{Ag}}\right]$ concentration is doubled

(2) [Cu²⁺] concentration is halved

(3) Size of Cu_(s) electrode is doubled

(4) size of Ag_(s) electrode is decreased to half

What will be the value of $∆\mathrm{G}°$ for the rection ${\mathrm{Cu}}^{+2} + \mathrm{Fe} \stackrel{ }{\rightleftharpoons } {\mathrm{Fe}}^{+2} + \mathrm{Cu} ,$

if ${\mathrm{E}}_{\raisebox{1ex}{${\mathrm{Cu}}^{+2}$}\!\left/ \!\raisebox{-1ex}{$\mathrm{Cu}$}\right.}^{\circ } = +0.34 \mathrm{V} \mathrm{and} {\mathrm{E}}_{\raisebox{1ex}{${\mathrm{Fe}}^{+2}$}\!\left/ \!\raisebox{-1ex}{$\mathrm{Fe}$}\right.}^{\circ } = -0.44 \mathrm{V}$$$

(1) -65.62 KJ

(2) -75.27 KJ

(3) -150.54 KJ

(4) +150.54 KJ

At 298 K the Emf of the following cell is:

\(\small{Pt|H_{2}(1 \ atm)|H^{+}(0.02 \ M) \ || \ H^{+}(0.01 \ M)|H_{2}(1 \ atm)|Pt}\)

1. - 0.017 V

2. 0.0295 V

3. 0.1 V

4. 0.059 V

At 25$°$C temperature Zn electrode is placed in 0.1M solution of zinc salt then what will be the reduction potential ? If it is assumed that salt dissociates 25% at this dilution (${\mathrm{E}}_{\raisebox{1ex}{${\mathrm{Zn}}^{2+}$}\!\left/ \!\raisebox{-1ex}{$\mathrm{Zn}$}\right.}^{°} = -0.76 \mathrm{V}$)

(1) -0.713 V

(2) - 0.81 V

(3) + 0.778 V

(4) - 0.84 V

The reduction potential of Hydrogen electrode is -118mV then the concentration of ${\mathrm{H}}^{\oplus }$ion in solution will be :-

(1) 10^-4M

(2) 2M

(3) 0.01M

(4) 10^-3M