${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{N}}_2\mathrm{Cl}+{\mathrm{H}}_3{\mathrm{PO}}_2+{\mathrm{H}}_2\mathrm{O}$:

The product from the above reaction would be -

$1.{\mathrm{C}}_6{\mathrm{H}}_5\mathrm{NC}$

$2. {\mathrm{C}}_6{\mathrm{H}}_6{\mathrm{CH}}_3$

$3.{\mathrm{C}}_6{\mathrm{H}}_5\mathrm{CN}$

$4. {\mathrm{C}}_6{\mathrm{H}}_6$

 

The primary amine is -

1. ${\left({\mathrm{CH}}_3\right)}_2{\mathrm{CHNH}}_2$

2. ${{\mathrm{CH}}_3\left({\mathrm{CH}}_2\right)}_2\mathrm{NH}-{\mathrm{CH}}_3$

3. ${{\mathrm{CH}}_3\left({\mathrm{CH}}_2\right)}_2\mathrm{N}{\left({\mathrm{CH}}_3\right)}_2$

4. None of the above

Which of the following is a secondary amine is -

$1. {\mathrm{CH}}_3{\left({\mathrm{CH}}_2\right)}_2{\mathrm{NH}}_2$
$2. {\left({\mathrm{CH}}_3{\mathrm{CH}}_2\right)}_2{\mathrm{NCH}}_3$
$3. {\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NHCH}}_3$
$4. {\left({\mathrm{CH}}_3\right)}_3{\mathrm{NH}}_2$

The tertiary amine is-

$1. {\left({\mathrm{CH}}_3{\mathrm{CH}}_2\right)}_2{\mathrm{NCH}}_3$
$2. {\left({\mathrm{CH}}_3\right)}_3{\mathrm{NH}}_2$
$3. \mathrm{m}-{\mathrm{BrC}}_6{\mathrm{H}}_4{\mathrm{NH}}_2$
$4. \mathrm{None\; of }\mathrm{the\; above}$

Which of the following tests is used to distinguish aniline from benzylamine?

1. Nitrous acid.

2. Reduction Reaction

3. Hinsberg reagent

4. Lucas test

The chemical test used to distinguish between aniline and N-methyl aniline is:

1. Carbylamine test 

2. Hoffmann bromamide reaction

3. Acetylation

4. None of above

The chemical test used to distinguish between methylamine and dimethylamine is:

1. Hoffmann bromamide reaction

2. Hinsberg's reagent 

3. Carbylamine test

4. Both 2 and 3

X, Y, and Z in the above sequence are:

1. X= Fe/HCl, Y= ${\mathrm{Br}}_2/{\mathrm{FeCl}}_3$, and Z = ${\mathrm{H}}_2\mathrm{O}$/ warm

2. X= ${\mathrm{Br}}_2/{\mathrm{FeCl}}_3$, Y= Fe/HCl, and Z = ${\mathrm{H}}_2\mathrm{O}$/ warm

3.  X= $\mathrm{HBr}/ \mathrm{hv}$, Y= Fe/HCl, and Z = ${\mathrm{H}}_3{\mathrm{PO}}_2$

4. X = $\mathrm{HBr}/ \mathrm{hv}$ Y = ${\mathrm{Br}}_2/{\mathrm{FeCl}}_3$, and Z = ${\mathrm{H}}_3{\mathrm{PO}}_2$

X, and Y in the following sequence are :

1.	X = Br2 / CS2 , and Y =
2.	X = Br2 / H2O and Y =
3.	X = Br2 / CS2 , and Y =
4.	X = Br2 / H2O and Y =

Benzyl chloride $\stackrel{\mathrm{KCN}}{\to }$ X $\stackrel{LiAl{H}_4}{\to }$ Y

The product X and Y are -

1. 2-Phenylethanenitrile and Benzoic acid

2. Benzonitrile and Benzoic acid

3. 2-Phenylethanenitrile and 2-Phenylethanamine

4. Benzonitrile and 2-Phenylethanamine