Time taken by an object falling from rest to cover the height of h₁ and h₂ is respectively t₁ and t₂ . Then the ratio of t₁ to t₂ is 

(1) h₁ : h₂

(2) $\sqrt{h_1}:\sqrt{h_2}$

(3) h₁ : 2h₂

(4) 2h₁ : h₂

A body is thrown vertically up from the ground. It reaches a maximum height of \(100\) m in \(5\) s. After what time will it reach the ground from the position of maximum height?

A body thrown vertically upwards with an initial velocity u reaches maximum height in 6 seconds. The ratio of the distances travelled by the body in the first second and the seventh second is 

(1) 1 : 1

(2) 11 : 1

(3) 1 : 2

(4) 1 : 11

A particle is thrown vertically upwards. If its velocity at half of the maximum height is 10 m/s, then maximum height attained by it is (Take g = 10 m/s²) 

(1) 8 m

(2) 10 m

(3) 12 m

(4) 16 m

A body, thrown upwards with some velocity, reaches the maximum height of 20m. Another body with double the mass thrown up, with double initial velocity will reach a maximum height of 

(1) 200 m

(2) 16 m

(3) 80 m

(4) 40 m

A balloon starts rising from the ground with an acceleration of 1.25 m/s² . After 8s, a stone is released from the balloon. The stone will (g = 10 m/s²) 

(1) Reach the ground in 4 second

(2) Begin to move down after being released

(3) Have a displacement of 50 m

(4) Cover a distance of 40 m in reaching the ground

A body is thrown vertically upwards with a velocity u. Find the true statement from the following:

(1) Both velocity and acceleration are zero at its highest point

(2) Velocity is maximum and acceleration is zero at the highest point

(3) Velocity is maximum and acceleration is g downwards at its highest point

(4) Velocity is zero at the highest point and maximum height reached is $u^2/2g$

A man throws a ball vertically upward and it rises through 20 m and returns to his hands. What was the initial velocity (u) of the ball and for how much time (T) it remained in the air $[g=10m/s^2]$ 

(1) u = 10 m/s, T = 2s

(2) u = 10 m/s, T = 4s

(3) u = 20 m/s, T = 2s

(4) u = 20 m/s, T = 4s

A particle when thrown moves such that it passes from the same height at 2 sec and 10 sec, the height is:

(1) g

(2) 2g

(3) 5g

(4) 10g

From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 m/s. The ratio of the distances, covered by it in the 3^rd and 2^nd seconds of the motion is (Take $g=10m/s^2$) 

1. 5 : 7  

2. 7 : 5

3. 3 : 6

4. 6 : 3