A man throws a ball vertically upward and it rises through 20 m and returns to his hands. What was the initial velocity (u) of the ball and for how much time (T) it remained in the air $[g=10m/s^2]$ 

(1) u = 10 m/s, T = 2s

(2) u = 10 m/s, T = 4s

(3) u = 20 m/s, T = 2s

(4) u = 20 m/s, T = 4s

A particle when thrown moves such that it passes from the same height at 2 sec and 10 sec, the height is:

(1) g

(2) 2g

(3) 5g

(4) 10g

From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 m/s. The ratio of the distances, covered by it in the 3^rd and 2^nd seconds of the motion is (Take $g=10m/s^2$) 

1. 5 : 7  

2. 7 : 5

3. 3 : 6

4. 6 : 3

Two balls A and B of same masses are thrown from the top of the building. A, thrown upward with velocity v and B, thrown downward with velocity v, then 

(1) Velocity of A is more than B at the ground

(2) Velocity of B is more than A at the ground

(3) Both A & B strike the ground with same velocity

(4) None of these

A cricket ball is thrown up with a speed of 19.6 ms^–1. The maximum height it can reach is:

(1) 9.8 m

(2) 19.6 m

(3) 29.4 m

(4) 39.2 m

A body falling from a high Minaret travels \(40\) meters in the last \(2\) seconds of its fall to the ground. The height of the Minaret in meters is: (take \(g = 10~\text{ms}^{-2}\)) 
1. \(60\)
2. \(45\)
3. \(80\)
4. \(50\)

A body falls from a height $h=200m$ (at New Delhi). The ratio of distance travelled in each 2 sec during t = 0 to t = 6 second of the journey is 

(1) 1 : 4 : 9

(2) 1 : 2 : 4

(3) 1 : 3 : 5

(4) 1 : 2 : 3

A man drops a ball downside from the roof of a tower of height 400 meters. At the same time another ball is thrown upside with a velocity 50 meter/sec. from the surface of the tower, then they will meet at which height from the surface of the tower 

(1) 100 meters

(2) 320 meters

(3) 80 meters

(4) 240 meters

Two balls are dropped from heights h and 2h respectively from the earth surface. The ratio of time of these balls to reach the earth is 

(1) $1:\sqrt{2}$

(2) $\sqrt{2}$ : 1

(3) 2 : 1

(4) 1 : 4