In the Wheatstone's bridge shown, P = 2 Ω, Q = 3 Ω, R = 6 Ω and S = 8 Ω. In order to obtain balance, shunt resistance across 'S' must be [SCRA 1998]

(1) 2 Ω

(2) 3 Ω

(3) 6 Ω

(4) 8 Ω

Potential difference between the points P and Q in the electric circuit shown is 

(1) 4.5 V

(2) 1.2 V

(3) 2.4 V

(4) 2.88 V

In a typical Wheatstone network, the resistances in cyclic order are A = 10 Ω, B = 5 Ω, C = 4 Ω and D = 4 Ω for the bridge to be balanced 

(1) 10 Ω should be connected in parallel with A

(2) 10 Ω should be connected in series with A

(3) 5 Ω should be connected in series with C

(4) 5 Ω should be connected in parallel with B

In the circuit shown in figure, the current drawn from the battery is 4A. If 10 Ω resistor is replaced by 20 Ω resistor, then current drawn from the circuit will be 

(1) 1 A

(2) 2 A

(3) 3 A

(4) 4 A

If each of the resistance of the network shown in the figure is R, the equivalent resistance between A and B is 

(1) 5 R

(2) 3 R

(3) R

(4) R/2

Thirteen resistances each of resistance R ohm are connected in the circuit as shown in the figure below. The effective resistance between A and B is 

(1) 2R Ω

(2) $\frac{4R}{3}\Omega$

(3) $\frac{2R}{3}\Omega$

(4) R Ω

For what value of unknown resistance X, the potential difference between B and D will be zero in the circuit shown in the figure 

(1) 4 Ω

(2) 6 Ω

(3) 2 Ω

(4) 5 Ω

An unknown resistance R₁ is connected in series with a resistance of 10 Ω. This combinations is connected to one gap of a metre bridge while a resistance R₂ is connected in the other gap. The balance point is at 50 cm. Now, when the 10 Ω resistance is removed the balance point shifts to 40 cm. The value of R₁ is (in ohm) 

(1) 60

(2) 40

(3) 20

(4) 10

A wire has a resistance of 6 Ω. It is cut into two parts and both half values are connected in parallel. The new resistance is :

(1) 12 Ω

(2) 1.5 Ω

(3) 3 Ω

(4) 6 Ω