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Q. No.Human genome is said to have approximately
1. \(3 \times 10^9 \mathrm{bp}\)
2. \(3 \times 10^6 b p\)
3. \(6.6 \times 10^6 \mathrm{bp}\)
4. \(3.3 \times 10^6 \mathrm{bp} \)
Subtopic: Human Genome Project |
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How many total number of genes are found in human genome?
1. 18,000
2. 30,000
3. 13,000
4. 4,000
1. 18,000
2. 30,000
3. 13,000
4. 4,000
Subtopic: Human Genome Project |
90%
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Subtopic: Human Genome Project |
92%
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In humans, the largest gene is present on
1. Chromosome-1
2. Y-chromosome
3. X-chromosome
4. Chromosome-7
1. Chromosome-1
2. Y-chromosome
3. X-chromosome
4. Chromosome-7
Subtopic: Human Genome Project |
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Subtopic: Human Genome Project |
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SNPs stands for
1. Single nucleoside polymorphism
2. Simple nucleotide polymorphism
3. Single nucleotide polymorphism
4. Simple nucleoside polymorphism
1. Single nucleoside polymorphism
2. Simple nucleotide polymorphism
3. Single nucleotide polymorphism
4. Simple nucleoside polymorphism
Subtopic: Human Genome Project |
84%
From NCERT
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Select the incorrect statement.
1. DNA is genetic material in all organisms except some viruses
2. RNA is genetic material in riboviruses.
3. Term 'factor' was used by Mendel
4. DNA is a basic substance which was first identified by Altmann.
1. DNA is genetic material in all organisms except some viruses
2. RNA is genetic material in riboviruses.
3. Term 'factor' was used by Mendel
4. DNA is a basic substance which was first identified by Altmann.
Subtopic: The DNA |
85%
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Select the mis-matched pair.
| 1. | \(\phi \times 174\) bacteriophage | - | 5386 bases |
| 2. | \(\lambda\) phage | - | ds RNA |
| 3. | E. coli | - | ds DNA |
| 4. | Human genome | - | 3.3 x109 bp |
Subtopic: The DNA |
62%
From NCERT
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Adenine and guanine are
1. Heterocyclic
2. Have nitrogen only at position 1 and 3
3. 9- membered double ring structures
4. Both (1) & (3)
1. Heterocyclic
2. Have nitrogen only at position 1 and 3
3. 9- membered double ring structures
4. Both (1) & (3)
Subtopic: The DNA |
82%
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Mark the odd one w.r.t. chargaff's rule
1. A + G = T + C
2. A + T / C + G = 0.92 for E.coli
3. Purine guanine is equimolar to pyrimidine cytosine
4. Applicable for both single as well as double stranded DNA
1. A + G = T + C
2. A + T / C + G = 0.92 for E.coli
3. Purine guanine is equimolar to pyrimidine cytosine
4. Applicable for both single as well as double stranded DNA
Subtopic: DNA Double Helix |
66%
From NCERT
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