Two identical cells send the same current in 2 Ω resistance, whether connected in series or in parallel. The internal resistance of the cell should be 

(1) 1 Ω

(2) 2 Ω

(3) $\frac{1}{2}\Omega$

(4) 2.5 Ω

The internal resistances of the two cells shown are 0.1 Ω and 0.3 Ω. If R = 0.2 Ω, the potential difference across the cell :

(1) B will be zero

(2) A will be zero

(3) A and B will be 2V

(4) A will be > 2V and B will be < 2V

The figure shows a network of currents. The magnitude of currents is shown here. The current i will be 

(1) 3 A

(2) 13 A

(3) 23 A

(4) – 3 A

A battery of emf \(E\) and internal resistance \(r\) is connected to a variable resistor \(R\) as shown below. Which one of the following is true​​​​​?

Consider the circuit given here with the following parameters E.M.F. of the cell = 12 V. Internal resistance of the cell = 2 Ω. Resistance R = 4 Ω. Which one of the following statements is true.

(1) Rate of energy loss in the source is = 8 W

(2) Rate of energy conversion in the source is 16 W

(3) Power output in R is = 8 W

(4) Potential drop across R is = 16 V

The current in the arm \(CD\) of the circuit will be:
             

1. \(i_{1} + i_{2}\)

2. \(i_{2} + i_{3}\)

3. \(i_{1} + i_{3}\)

4. \(i_{1} - i_{2} + i_{3}\)

Two non-ideal identical batteries are connected in parallel. Consider the following statements :

(i) The equivalent e.m.f. is smaller than either of the two e.m.f.s

(ii) The equivalent internal resistance is smaller than either of the two internal resistances

(1) Both (i) and (ii) are correct

(2) (i) is correct but (ii) is wrong

(3) (ii) is correct but (i) is wrong

(4) Both (i) and (ii) are wrong

Consider the circuit shown in the figure below. The current \(I_3\) is equal to:

1. \(5\) A

2. \(3\) A

3. \(-3\) A

4. \(\frac{-5}{6}\) A

If $V_{AB}=4V$ in the given figure, then resistance X will be:

1. 5 Ω

2. 10 Ω

3. 15 Ω

4. 20 Ω

The number of dry cells, each of e.m.f. 1.5 volt and internal resistance 0.5 ohm that must be joined in series with a resistance of 20 ohms, so as to send a current of 0.6 amperes through the circuit is 

(1) 2

(2) 8

(3) 10

(4) 12