An organic compound X having molecular formula C₅H₁₀O yields phenyl hydrazone and

gives negative response to the iodoform test and Tollen's test. It produces n-pentane on

reduction. X could be:

1. Pentenal

2. 2-Pentanone

3. 3-Pentanone

4. n-Amyl alcohol

Which of the following will not be soluble in sodium hydrogen carbonate?

1. 2, 4,6 - trinitrophenol

2. benzoic acid

3. o-nitrophenol

4. Benzenesulphonic acid

In a reaction,

A is 

1. HgSO₄/H₂SO₄

2. Cu₂Cl₂

3. H₃PO₂ and H₂O

4. H⁺/H₂O

In the following sequence of reactions

 CH₃-Br $\stackrel{\mathrm{KCN}}{\to }$A$\stackrel{{\mathrm{H}}_3{\mathrm{O}}^{+}}{\to }$B$\underset{\mathrm{ether}}{\overset{{\mathrm{LiAlH}}_4}{\to }}$C

the end product C is:

1. Acetone

2. Methane

3. Acetaldehyde

4. Ethyl alcohol

CH₃CHO and C₆H₅CH₂CHO can be distinguished chemically by:

1. Benedict test

2. Iodoform test

3. Tollen's reagent test

4. Fehling solution test

In a set of reactions, m-bromobenzoic acid gave a product D. Identify the product D.

$\stackrel{{\mathrm{SOCl}}_2}{\to }$B$\stackrel{{\mathrm{NH}}_3}{\to }$C$\underset{{\mathrm{Br}}_2}{\overset{\mathrm{NaOH}}{\to }}\mathrm{D}$

1. 

2. 

3. 

4. 

What is the product obtained in the following reaction?

Which one is a nucleophilic substitution reaction among the following?

1.
2.
3.	\(\mathrm{CH}_3 \mathrm{CHO}+\mathrm{HCN} \rightarrow \mathrm{CH}_3 \mathrm{CH}(\mathrm{OH}) \mathrm{CN}\)
4.

The reaction of toluene with Cl₂ in presence of FeCl₃ gives 'X' and reaction in presence of

light gives 'Y'. Thus, 'X' and 'Y' are

1. X = Benzal chloride, Y = o-chlorotoluene

2. X = m-chlorotoluene, Y= p-chlorotoluene

3. X = o-and p-chlorotoluene, Y=trichloromethyl benzene

4. X = Benzyl chloride, Y = m-chlorotoluene

In a set of reactions, ethyl benzene yielded a product D.