A hypothetical electrochemical cell is shown below A l A+ (xM)l l B+ (yM) l B
The Emf measured is +0.20 V.The cell reaction is:-
(1) A+ + B → A + B+
(2) A+ + e- → A ; B+ + e- → B
(3) the cell reaction cannot be predicted
(4) A + B+ → A+ + B
The E° in the given diagram is,
(1) 0.5
(2) 0.6
(3) 0.7
(4) 0.8
At 298K the standard free energy of formation of H2O(l) is –237.20kJ/mole while that of its ionisation into H+ iion and hydroxyl ions is 80 kJ/mole, then the emf of the following cell at 298 K will be
H2(g,1 bar) | H+ (1M) || OH–(1M) | O2 (g, 1bar)
(1) 0.40 V
(2) 0.81 V
(3) 1.23 V
(4) –0.40 V
Which of the following cell can produce more electric work.
(1) pt,H2|NH4Cl||0.1MCH3COOH|H2,pt
(2) pt,H2|0.1MHCl||0.1MNaOH|H2,pt
(3) pt,H2|0.1MHCl||0.1MCH3COOK|H2,pt
(4) pt,H2|0.1MCH3COOK||0.1MHCl|H2,pt
At what does the following cell have its reaction at equilibrium?
Ag(s) | Ag2CO3(s) | Na2CO3 (aq) || KBr(aq) | AgBr(s) | Ag(s)
KSP = 8 × 10–12 for Ag2CO3 and KSP = 4 × 10–13 for AgBr
(1) × 10–7
(2) × 10–7
(3) × 10–7
(4) × 10–7
It is observed that the voltage of a galvanic cell using the reaction M(s) + xH+ Mx+ + H2 varies linearly with the log of the square root of the hydrogen pressure and the cube root of the Mx+ concentration. The value of x is:
1. 2
2. 3
3. 4
4. 5
Acetic acid has Ka = 1.8 × 10–5 while formic acid had Ka = 2.1 × 10–4. What would be the magnitude of the emf of the cell
Pt(H2) Pt(H2) at 25°C
(1) 0.0315 volt
(2) 0.0629 volt
(3) 0.0455 volt
(4) 0.0545 volt
Consider the cell Ag(s)|AgBr(s)|Br–(aq)||AgCl(s)|Cl–(aq)|Ag(s) at 25°C. The solubility product constants of AgBr & AgCl are respectively 5 × 10–13 & 1 × 10–10. For what ratio of the concentrations of Br– & Cl–ions would the emf of the cell be zero ?
(1) 1 : 200
(2) 1 : 100
(3) 1 : 500
(4) 200 : 1
Calculate the useful work of the reaction Ag(s) + 1/2Cl2(g) AgCl(s)
Given
If = 1 atmand T = 298 K
(1) 110 kJ/mol
(2) 220 kJ/mol
(3) 55kJ/mol
(4) 1000 kJ/mol