Four plates of equal area A are separated by equal distances d and are arranged as shown in the figure. The equivalent capacity is

(1) 2ε0Ad

(2) 3ε0Ad

(3) 4ε0Ad

(4) ε0Ad

Subtopic:  Combination of Capacitors |
 65%
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A parallel plate capacitor with air as medium between the plates has a capacitance of 10 μF. The area of capacitor is divided into two equal halves and filled with two media as shown in the figure having dielectric constant k1 = 2 and k2 = 4. The capacitance of the system will now be 

(1) 10 μF

(2) 20 μF

(3) 30 μF

(4) 40 μF

Subtopic:  Dielectrics in Capacitors |
 80%
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Three capacitors are connected to D.C. source of 100 volts shown in the adjoining figure. If the charge accumulated on plates of C1, C2 and C3 are qa,qb,qc,qd.qe and qf respectively, then 

(1) qb+qd+qf=1009C

(2) qb+qd+qf=0

(3) qa+qc+qe=50C

(4) qb=qd=qf

Subtopic:  Combination of Capacitors |
 68%
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n identical condensers are joined in parallel and are charged to potential V. Now they are separated and joined in series. Then the total energy and potential difference of the combination will be 

(1) Energy and potential difference remain the same

(2) Energy remains the same and the potential difference is nV

(3) Energy increases n times and potential difference is nV

(4) Energy increases n times and potential difference remains the same

Subtopic:  Energy stored in Capacitor |
 53%
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Five capacitors of 10 μF capacity each are connected to a d.c. potential of 100 volts as shown in the adjoining figure. The equivalent capacitance between the points A and B will be equal to 

(1) 40 μF

(2) 20 μF

(3) 30 μF

(4) 10 μF

Subtopic:  Combination of Capacitors |
 88%
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Three capacitors of capacitances \(3~\mu\text{F}\), \(9~\mu\text{F}\) and \(18~\mu\text{F}\) are connected once in series and another time in parallel. The ratio of equivalent capacitance in the two cases \(\frac{C_s}{C_p}\) will be:
1. \(1:15\)
2. \(15:1\)
3. \(1:1\)
4. \(1:3\)

Subtopic:  Combination of Capacitors |
 87%
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Four condensers each of capacity 4 μF are connected as shown in figure and VPVQ = 15 volts. The energy stored in the system is 

(1) 2400 ergs

(2) 1800 ergs

(3) 3600 ergs

(4) 5400 ergs

Subtopic:  Energy stored in Capacitor |
 83%
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In an adjoining figure are shown three capacitors C1, C2 and C3 joined to a battery. The correct condition will be (Symbols have their usual meanings) :

(1) Q1 = Q2 = Q3 and V1 = V2 = V3 = V

(2) Q1 = Q2 + Q3 and V = V1 + V2 + V3

(3) Q1 = Q2 + Q3 and V = V1 + V2

(4) Q2 = Q3 and V2 = V3

Subtopic:  Capacitance |
 67%
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In the circuit diagram shown in the adjoining figure, the resultant capacitance between P and Q is 

(1) 47 μF

(2) 3 μF

(3) 60 μF

(4) 10 μF

Subtopic:  Combination of Capacitors |
 89%
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Two capacitances of capacity C1 and C2 are connected in series and potential difference V is applied across it. Then the potential difference across C1 will be:

(1) VC2C1

(2) VC1+C2C1

(3) VC2C1+C2

(4) VC1C1+C2

Subtopic:  Combination of Capacitors |
 76%
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