A long wire AB is placed on a table. Another wire PQ of mass 1.0 g and length 50 cm is set to slide on two rails PS and QR. A current of 50A is passed through the wires. At what distance above AB, will the wire PQ be in equilibrium

                     

1. 25 mm                           

2. 50 mm

3. 70 mm                           

4. 100 mm

Subtopic:  Lorentz Force |
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A particle with charge \(q\), moving with a momentum \(p\), enters a uniform magnetic field normally. The magnetic field has magnitude \(B\) and is confined to a region of width \(d\), where \(d< \frac{p}{Bq}.\) The particle is deflected by an angle \(\theta\) in crossing the field, then:

       

1.  \(\sin \theta=\frac{Bqd}{p}\) 2. \(\sin \theta=\frac{p}{Bqd}\)
3. \(\sin \theta=\frac{Bp}{qd}\) 4. \(\sin \theta=\frac{pd}{Bq}\)
Subtopic:  Lorentz Force |
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The same current i = 2A is flowing in a wireframe as shown in the figure. The frame is a combination of two equilateral triangles ACD and CDE of side 1m. It is placed in uniform magnetic field B = 4T acting perpendicular to the plane of the frame. The magnitude of the magnetic force acting on the frame is:

                        

1. 24 N                                        
2. Zero
3. 16 N                                         
4.
 8 N

Subtopic:  Lorentz Force |
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In the given figure net magnetic field at O will be  i

   

(a) μ0i3πa4-π2                                 (b) μ0i3πa4+π2

(c) 2μ0i3πa4+π2                                  (d) 2μ0i3πa4-π2

Subtopic:  Magnetic Field due to various cases |
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In the following figure a wire bent in the form of a regular polygon of n sides is inscribed in a circle of radius a. Net magnetic field at centre will be \(\left(\theta = \frac{\pi}{n}\right)\)

 

                               

1. \(\frac{\left(\mu\right)_{o} i}{2 πa} tan \frac{\pi}{n}\)                                               
2. \(\frac{\left(\mu\right)_{0} n i}{2 πa} tan \frac{\pi}{n}\)

3.\(\frac{2}{\pi} \frac{n i}{a} \left(\mu\right)_{0} tan \frac{\pi}{n}\)                                           
4. \(\frac{n i}{2 a} \left(\mu\right)_{0} tan \frac{\pi}{n}\)

Subtopic:  Magnetic Field due to various cases |
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 The unit vectors \(\hat{i} ,   \hat{j}   ~\text{and} ~ \hat{k}\) are as shown below. What will be the magnetic field at \(O\) in the following figure?

                                          

1. \(\frac{\mu_{0}}{4 \pi} \frac{i}{a} 2 - \frac{\pi}{2} \hat{j}\)             
2. \(\frac{\mu_{0}}{4 \pi} \frac{i}{a}2 + \frac{\pi}{2} \hat{j}\)
3. \(\frac{\mu_{0}}{4 \pi} \frac{i}{a}2 + \frac{\pi}{2} \hat{i}\)             
4. \(\frac{\mu_{0}}{4 \pi} \frac{i}{a} 2 + \frac{\pi}{2} \hat{k}\) 


 

Subtopic:  Magnetic Field due to various cases |
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A particle of charge q and mass m moves in a circular orbit of radius r with angular speed ω. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends on

(1) ω and q

(2) ω, q and m

(3) q and m                     

(4) ω and m

Subtopic:  Magnetic Moment |
 72%
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A current \(I\) is carried by an elastic circular wire of length \(L\). It is placed in a uniform magnetic field \(B\) (out of paper) with its plane perpendicular to \(B'\text{s}\) direction. What will happen to the wire?

       

1. No force 2. A stretching force
3. A compressive force 4. A torque
Subtopic:  Current Carrying Loop: Force & Torque |
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Wires 1 and 2 carrying currents i1 and i2 respectively are inclined at an angle θ to each other. What is the force on a small element dl of wire 2 at a distance of r from wire 1 (as shown in figure) due to the magnetic field of wire 1

                                       

(a) μ02πri1i2dl tanθ                              (b) μ02πri1i2dl sinθ

(c) μ02πri1i2dl cosθ                               (d) μ04πri1i2dl sinθ

Subtopic:  Force between Current Carrying Wires |
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A conducting loop carrying a current I is placed in a uniform magnetic field pointing into the plane of the paper as shown. The loop will have a tendency to

                                    

(1) Contract                                       

(2) Expand 

(3) Move towards +ve x -axis               

(4) Move towards -ve x -axis

Subtopic:  Current Carrying Loop: Force & Torque |
 72%
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