A ring is made of a wire having a resistane 

R0=12Ω. Find the points A and B, as shown

in the figure, at which a current carrying 

conductor should be connected so that the 

resistance R of the sub circuit between these

points is equal to 8/3Ω

1. l1l2=58                    2. l1l2=13

3. l1l2=38                    4. l1l2=12

 

Subtopic:  Combination of Resistors |
 51%
From NCERT
NEET - 2012
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The power dissipated in the circuit shown in

the figure is 30 Watt. The value of R is :

(1) 20Ω

(2) 15Ω

(3) 10Ω

(4) 30Ω

Subtopic:  Heating Effects of Current |
 84%
From NCERT
NEET - 2012
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A cell having an emf ε internal resistance r is connected across a variable external  resistance R. As the resistance R is increased, the plot of potential difference V across R is given by

(a)    

(b) 

(c) 

(d) 

Subtopic:  EMF & Terminal Voltage |
 56%
From NCERT
NEET - 2012
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If power dissipated in the 9Ω resistor in the circuit shown is 36 W, the potential difference across the 2Ω resistor is

1. 8 V
2. 10 V
3. 2 V
4. 4 V

Subtopic:  Heating Effects of Current |
 78%
From NCERT
NEET - 2011
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A current of 2A flows through a 2Ω resistor

when connected across a battery. The same

battery supplies a current of 0.5 A when

connected across a 9Ω resistor. The internal

resistance of the battery is 

(1) 1/3Ω                   

(2) 1/4Ω

(3) 1Ω                       

(4) 0.5Ω

Subtopic:  EMF & Terminal Voltage |
 75%
From NCERT
NEET - 2011
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In the circuit in the figure, if the potential at point A is taken to be zero, the potential at point B is :

1. -1V                                          2. +2V

3. -2V                                          4. +1V

Subtopic:  Kirchoff's Voltage Law |
 57%
From NCERT
NEET - 2011
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Which one of the following bonds produces a solid that reflects light in the visible region and whose electrical conductivity decreases with temperature and has high melting point?

(1) metallic bonding

(2) van der Waals'bonding

(3) ionic bonding 

(4) covalent bonding

Subtopic:  Current & Current Density |
 62%
From NCERT
NEET - 2010
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A potentiometer circuit is set up as shown.The potential gradient across the potentiometer wire, is k volt/cm and the ammeter, present in the circuit, reads 1.0A when two way key is switched off. The balance points, when the key between the terminals (i) 1 and 2 (ii) 1and 3, is plugged in, are found to be at lengths l1cm and l2cm respectively.The magnitudes, of the resistors R and X, in ohm, are then, equal, respectively, to

(a)kl2-l1 and kl2

(b)kl1 and kl2-l1

(c)kl2-l1and kl1

(d)kl1 and kl2

Subtopic:  Meter Bridge & Potentiometer |
 66%
From NCERT
NEET - 2010
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 Consider the following two statements :

(1) Kirchhoff's junction law follows from the conservation of charge.

(2) Kirchhoff's loop law follows from the conservation of energy.

     Which of the following is correct?

(a) Both (A) and (B) are wrong

(b) (A) is correct and (B) is wrong

(3) (A)  is wrong and (B) is correct

(4) Both (A) and (B) are correct

Subtopic:  Kirchoff's Voltage Law |
 82%
From NCERT
NEET - 2010
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A wire of resistance \(12~\Omega \text{m}^{-1}\) is bent to form a complete circle of radius \(10~\text{cm}\). The resistance between its two diametrically opposite points, \(A\) and \(B\) as shown in the figure, is:

                         
1. \(0.6\pi~\Omega\)
2. \(3~\Omega\)
3. \(6\pi~\Omega\)
4. \(6~\Omega\)

Subtopic:  Combination of Resistors |
 58%
From NCERT
NEET - 2009
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