Two condensers C1 and C2 in a circuit are joined as shown in figure. The potential of point A is V1 and that of B is V2. The potential of point D will be 

(1) 12(V1+V2)

(2) C2V1+C1V2C1+C2

(3) C1V1+C2V2C1+C2

(4) C2V1C1V2C1+C2

Subtopic:  Combination of Capacitors |
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The combined capacity of the parallel combination of two capacitors is four times their combined capacity when connected in series. This means that 

(1) Their capacities are equal

(2) Their capacities are 1 μF and 2 μF

(3) Their capacities are 0.5 μF and 1 μF

(4) Their capacities are infinite

Subtopic:  Combination of Capacitors |
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In the given network capacitance, C1 = 10 μF, C2 = 5 μF and C3 = 4 μF. What is the resultant capacitance between A and B 

(1) 2.2 μF

(2) 3.2 μF

(3) 1.2 μF

(4) 4.7 μF

Subtopic:  Combination of Capacitors |
 87%
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The equivalent capacitance between \(A\) and \(B\) is:

         

1. \(2~\mu\text{F}\) 2. \(3~\mu\text{F}\)
3. \(5~\mu\text{F}\) 4. \(0.5~\mu\text{F}\)
Subtopic:  Combination of Capacitors |
 72%
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In the circuit shown in figure, each capacitor has a capacity of 3 μF. The equivalent capacity between A and B is 

(1) 34μF

(2) 3 μF

(3) 6 μF

(4) 5 μF

Subtopic:  Combination of Capacitors |
 57%
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In the figure, three capacitors each of capacitance 6 pF are connected in series. The total capacitance of the combination will be 

(1) 9 × 10–12 F

(2) 6 × 10–12 F

(3) 3 × 10–12 F

(4) 2 × 10–12 F

Subtopic:  Combination of Capacitors |
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Equivalent capacitance between A and B is 

(1) 8 μF

(2) 6 μF

(3) 26 μF

(4) 10/3 μF

Subtopic:  Combination of Capacitors |
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In the figure a capacitor is filled with dielectrics. The resultant capacitance is 

(1) 2ε0Ad1k1+1k2+1k3

(2) ε0Ad1k1+1k2+1k3

(3) 2ε0Ad[k1+k2+k3]

(4) None of these

Subtopic:  Combination of Capacitors |
 63%
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Three capacitors of capacitance 3 μF, 10 μF and 15 μF are connected in series to a voltage source of 100V. The charge on 15 μF is 

(1) 50 μC

(2) 100 μC

(3) 200 μC

(4.) 280 μC

Subtopic:  Combination of Capacitors |
 82%
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Two capacitors \(C_1 = 2~\mu\text{F}\) and \(C_2 = 6~\mu \text{F}\) in series, are connected in parallel to a third capacitor \(C_3= 4~\mu\text{F}\). This arrangement is then connected to a battery of \(\text{emf}= 2~\text{V}\), as shown in the figure. How much energy is lost by the battery in charging the capacitors? 


1. \(22\times 10^{-6}~\text{J}\)
2. \(11\times 10^{-6}~\text{J}\)
3. \(\frac{32}{3}\times 10^{-6}~\text{J}\)
4. \(\frac{16}{3}\times 10^{-6}~\text{J}\)

Subtopic:  Energy stored in Capacitor |
 78%
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