An organic compound having molecular formula C₇H₈O is neither soluble in NaOH nor gives blue color with FeCl₃. The compound is:

1. C₆H₅.CH₂OH                 
2. ${\mathrm{C}}_6{\mathrm{H}}_4{<}_{\mathrm{OH}}^{{\mathrm{CH}}_3}$
3. C₆H₅.OCH₃                 
4. None of these

Which one of the following on oxidation gives a ketone?                   

1. Primary alcohol                      2. Secondary alcohol

3. Tertiary alcohol                      4. All of these

In the following sequence of reactions, the product (C) is: 

CH₃CHO$\underset{\mathrm{Pd}}{\overset{{\mathrm{H}}_2}{\to }}$ (A) $\stackrel{\mathrm{Na}}{\to }$ (B) $\stackrel{{\mathrm{CH}}_3\mathrm{I}}{\to }$  (C)

1. Alcohol.                                 
2. Ether.
3. Alkene.                                 
4. None of the above.

The formula of phenoxy benzene is-

1. C₆H₅C₆H₅                             

2. C₆H₅-O-C₆H₅

3. C₆H₅-O-C₆H₆                         

4. None of the above

Which of the following reacts with water

1. CHCl₃                                     

2. CCl₄

3. CCl₃CHO                               

4. CH₂ClCH₂Cl

Ether and benzene can be separated by:-

1. Filtration

2. Distillation

3. Crystallization

4. Sublimation

Picric acid and benzoic acid can be distinguished by:

1. Aqueous NaHCO₃                   

2. Aqueous $\mathrm{NaOH}$

3. Aqueous FeCl₃                       

4. Aqueous Na₂CO₃  

Primary alcohols can be obtained from the reaction of the RMgX with:

1. HCHO                       

2. H₂O

3. CO₂                         

4. CH₃CHO

Oxidation of allylic alcohol, (CH₂=CH-CH₂OH) gives a mixture of oxalic acid and formic acid. If this oxidation is done in presence of bromine. One would expect only:

1. Oxalic acid

2. Formic acid

3. Succinic acid

4. Acrylic acid

Consider the following reaction, 

Ethanol $\stackrel{{\mathrm{PBr}}_3}{\to }$X$\stackrel{\mathrm{Alc}.\mathrm{KOH}}{\to }$Y$\underset{\left(\mathrm{ii}\right){\mathrm{H}}_2\mathrm{O}, \mathrm{heat}}{\overset{\left(\mathrm{i}\right) {\mathrm{H}}_2{\mathrm{SO}}_4, \mathrm{room} \mathrm{temperature}}{\to }}$Z

product Z is:

1. CH₂=CH₂

2. CH₃CH₂OCH₂CH₃

3. CH₃CH₂OSO₃H

4. CH₃CH₂OH