The displacement of a particle is given by \(y = a+bt+ct^2-dt^4\). The initial velocity and initial acceleration, respectively, are: \(\left(\text{Given:}~ v=\frac{dx}{dt}~\text{and}~a=\frac{d^2x}{dt^2}\right)\)
1. \(b, -4d\)
2. \(-d, 2c\)
3. \(b, 2c\)
4. \(2c, -4d\)
The momentum is given by p=4t+1, the force at t=2s is-
(A) 4 N
(B) 8 N
(C) 10 N
(D) 15 N
If the momentum of a particle is given by P=(180-8t) kg m/s, then its force will be-
(1) Zero
(2) 8 N
(3) -8 N
(4) 4 N
The maximum value of the function \(7 + 6 x - 9 x^{2}\) is:
1. \(8\)
2. \(-8\)
3. \(4\)
4. \(-4\)
If \(f \left(x\right) = x^{2} - 2 x + 4\), then \(f(x)\) has:
1. | \(x=1\). | a minimum at
2. | \(x=1\). | a maximum at
3. | no extreme point. |
4. | no minimum. |
A particle is moving along x-axis. The velocity v of particle varies with its position x as . Find velocity of particle as a function of time t given that at t=0, x=1 .
1.
2.
3.
4. None of these
A vector is directed along west of north direction and another vector along south of east. Their resultant cannot be in ____________ direction.
(1) North
(2) East
(3) North-East
(4) South
ABCD is a quadrilateral. Forces act at a point. Their resultant is
(A)
(B)
(C) zero vector
(D)
The maximum and minimum magnitude of the resultant of two vectors are 17 units and 7 units respectively. Then the magnitude of resultant of the vectors when they act perpendicular to each other is:
(1) 14
(2) 16
(3) 18
(4) 13
A vector makes an angle of and makes an angle of with the X-axis. The magnitudes of these vectors are 3 m and 4 m respectively. Find the magnitude of the resultant.
(A)
(B)
(C)
(D)