For the reaction:

H2S (g) + Cl2 (g)  2 HCl (g) + S (s)

The correct statement(s) in the balanced equation is(are):

a. H2S is oxidised
b. Cl2 is reduced
c. H2S is reduced
d. Cl2 is oxidised

1. a, b
2. b, c
3. c, d
4. a, d

Subtopic:  Oxidizing & Reducing Agents |
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2 Na(s) + H2(g)  2 NaH (s)

The incorrect statement among the following regarding above mentioned reaction is:

1. Na gets oxidised
2. It is a redox reaction
3. NaH is an ionic hydride
4. None of the above

Subtopic:  Redox Titration & Type of Redox |
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Match the items in column I with column II.
(O.S = oxidation state)

Column I Column II
a. Au O.S in HAuCl4 i. +2
b. Tl O.S in Tl2O ii. +1
c. Fe O.S in FeO iii. +3
d. Cu O.S in CuI

1. a=i; b=ii; c=iii; d=ii
2. a=iii; b=i; c=ii; d=ii
3. a=iii; b=ii; c=i; d=ii
4. a=ii; b=i; c=iii; d=ii
Subtopic:  Introduction to Redox and Oxidation Number |
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Consider the given reaction:
\(2 \mathrm{Cu}_2 \mathrm{O}(s)+\mathrm{Cu}_2 \mathrm{~S}(s) \rightarrow 6 \mathrm{Cu}(s)+\mathrm{SO}_2(g)\)


Which of the following statements about the given reaction is correct?

1. Cu is reduced and Cu(I) is an reductant.
2. Sulphur is reduced and S in Cu2S acts as oxidant.
3. Cu(I) is an oxidant and Cu(I) is reduced.
4. Sulphur is reduced and copper is oxidised.

Subtopic:  Oxidizing & Reducing Agents |
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The species among the following that does not show a disproportionation reaction is-

ClO, ClO2\(ClO_{3}^{-}\) and ClO4

1. ClO
2. ClO2
3.
ClO4
4. \(ClO_{3}^{-}\)

Subtopic:  Redox Titration & Type of Redox |
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Match the items in column I with the items in column II.

Column I Column II
a. N2 (g) + O2 (g)  2 NO (g) i. Disproportionation redox reaction
b. 2Pb(NO3)2(s)  2PbO(s) + 4 NO2 (g) + O2 (g) ii. Decomposition redox reaction
c. NaH(s) + H2O(l)  NaOH(aq) + H2 (g) iii. Combination redox reactions
d. 2NO2(g) + 2OH(aq)  NO2(aq) + NO3 (aq) + H2O(l) iv. Displacement redox reaction
 
1. a = iii; b = ii; c = iv; d = i
2. a = iii; b = iv; c = i; d = ii
3. a = ii; b = iii; c = iv; d = i
4. a = iv; b = i; c = iii; d = ii
Subtopic:  Redox Titration & Type of Redox |
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Consider the following reaction:

Pb3O4 + 8HCl  A +  B + 4H2O

A and B are, respectively,:

1. A= PbCl4;  B= PbCl2
2. A= PbCl2;  B= Cl2 
3. A= PbCl4; B=Cl2
4. A = PbCl2; B = O2

Subtopic:  Redox Titration & Type of Redox |
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Consider the following equation:

Cr2O72–(aq) + 3SO32– (aq)+ 8H+(aq) →  A + B +4H2O(l)

The product A and B are respectively:

1. 2Cr2+; 3SO2

2. 2Cr+; S2O7 2-

3. 2Cr3+; 3SO4 2-

4. 2Cr3+; 3HSO42-


 

Subtopic:  Balancing of Equations |
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aMnO4(aq) + bBr(aq) + cH2O(l)  dMnO2(s) + eBrO3 (aq) + fOH(aq)

The value of c, d and f  in the above mentioned reaction are respectively:
1. c = 1; d = 2; f = 2 2. c = 2; d = 1; f = 2
3. c = 2; d = 2; f = 1 4. c = 1; d = 1; f = 1
Subtopic:  Balancing of Equations |
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Permanganate(VII) ion, MnO4 in basic solution oxidizes iodide ion, I to produce molecular iodine (I2) and manganese (IV) oxide (MnO2). The reaction is as follows:

aI(aq) + bMnO4(aq) + cH2O(l)  dI2(s) + eMnO2(s) + fOH(aq)

The value of b, d and f are-

1. b = 2; d = 3; f = 8 2. b = 1; d = 3; f = 8
3. b = 3; d = 8; f = 2 4. b = 8; d = 3; f = 2
Subtopic:  Balancing of Equations |
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