The oxidation state of potassium in KO₂ is-

1. +2
2. +1
3. 0
4. +4

Consider the following data
E^o Cl₂/Cl^– = +1.36,  E^o I₂/I^– =+ 0.53,  E^o  Ag⁺ /Ag = +0.79,  E^o Na⁺/Na = –2.71 and  Li⁺ /Li is – 3.04.
Arrange the following ionic species in decreasing order of reducing strength: 

I^–, Ag, Cl^–, Li, Na.

1. Li > Na > I^– > Ag > Cl^–

2. Cl^– > Na > I^– > Ag > Li

3. Li < Na < I^– < Ag < Cl^–

4. Li > Na = I^– > Ag > Cl^–

KO₂ is paramagnetic in nature ,It is because -
1. K⁺ ion contains unpaired electron
2. \(O_{2}^{2-}\) ion contains unpaired electron
3. \(O_{2}^{-}\) ion contains unpaired electron in \( \pi^{*}\) MO
4. \(O_{2}^{-}\) ion contains unpaired electron in \( \pi\) MO

The solubility of alkaline earth metal hydroxides in water increases down the group because-
 

The correct statement above the following is -