105 coloumb charge liberated 1 gm silver (Ag). If the charge is doubled
then the amount of liberated Ag will be:

1. 1 gm 2. 2 gm
3. 3 gm 4. 4 gm
Subtopic:  Faraday’s Law of Electrolysis |
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The concentration of ZnCl2 solution will change when it is placed in a container which is made of:

1. Al 2. Cu
3. Ag 4. None
Subtopic:  Electrochemical Series |
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The cell reaction of an electrochemical cell is \(Cu^{2+}(C_{1}) + Zn \to Cu + Zn^{2+}(C_{2})\).

The change in free energy will be the function of:

\(1. \ ln (C_{1}+C_{2})\)
2. \(ln (\frac{C_{2}}{C_{1}})\)
\(3. \ ln C_{2}\)
\(4. \ lnC_{1}\)

Subtopic:  Relation between Emf, G, Kc & pH |
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The value of E0 cell for the following reaction is:
\(Cu^{2+}+ Sn^{2+}\to Cu +Sn^{4+ } \)

(Given, equilibrium constant is 106)

1. 0.17 2. 0.01
3. 0.05 4. 1.77
Subtopic:  Electrode & Electrode Potential |
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For the disproportionation of copper:

2Cu+ → C u2+ + C u, E° is:
(Given E° for Cu+2/Cu is 0.34 V & Eº for Cu+2/Cuis 0.15 V )

1. 0.49 V

2. – 0.19 V

3. 0.38 V

4. – 0.38 V

Subtopic:  Electrode & Electrode Potential |
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A cell reaction become spontaneous when:

1. ∆Gº is negative

2. ∆Gº is positive

3. ERed° is positive

4. ERed° is negative

Subtopic:  Relation between Emf, G, Kc & pH |
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At infinite dilution, equivalent conductances of Ba+2 & Cl ions are 127 & 76 ohm–1cm–1 eq–1 respectively. Equivalent conductance (ohm–1cm–1 eq–1) of BaCl2 at infinite dilution is:

1. 139.5

2. 101.5

3. 203

4. 279

Subtopic:   Kohlrausch Law & Cell Constant |
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In electrolysis of NaCl when Pt electrode is taken then H2 is liberated at the cathode while with Hg cathode it forms sodium amalgam because:

1. Hg is more inert than Pt
2. More voltage is required to reduce H+ at Hg than at Pt
3. Na is dissolved in Hg while it does not dissolve in Pt
4. The concentration of H+ ions is larger when the Pt electrode is taken
Subtopic:  Electrode & Electrode Potential |
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In the silver plating of copper, K[Ag(CN)2] is used instead of AgNO3. The reason is:
 

1. A thin layer of Ag is formed on Cu
2. More voltage is required
3. Ag+ ions are completely removed from the solution
4. Less availability of Ag+ ions, as Cu can not displace Ag from [Ag(CN)2] ion
Subtopic:  Electrochemical Series |
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Consider the following  reaction:

\(\frac{4}{3} \mathrm{Al}(\mathrm{s})+\mathrm{O}_2(\mathrm{~g}) \rightarrow \frac{2}{3} \mathrm{Al}_2 \mathrm{O}_3(\mathrm{~s})\), G=-827 KJ mol-1.
The minimum e.m.f. required to carry out the electrolysis of Al2O3 is:
(F = 96500 C mol–1)

1. 2.14 V

2. 4.28 V

3. 6.42 V

4. 8.56 V

Subtopic:  Electrode & Electrode Potential |
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