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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyPrefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot
NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyPrefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot
NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biology1. | angular momentum |
2. | coefficient of thermal conductivity |
3. | torque |
4. | gravitational constant |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biology1. | both units and dimensions |
2. | units but no dimensions |
3. | dimensions but no units |
4. | no units and no dimensions |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyPrefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot
NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyPrefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot
NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyList-I | List-II | ||
(a) | Gravitational constant (\(G\)) | (i) | \([{L}^2 {~T}^{-2}] \) |
(b) | Gravitational potential energy | (ii) | \([{M}^{-1} {~L}^3 {~T}^{-2}] \) |
(c) | Gravitational potential | (iii) | \([{LT}^{-2}] \) |
(d) | Gravitational intensity | (iv) | \([{ML}^2 {~T}^{-2}]\) |
(a) | (b) | (c) | (d) | |
1. | (iv) | (ii) | (i) | (iii) |
2. | (ii) | (i) | (iv) | (iii) |
3. | (ii) | (iv) | (i) | (iii) |
4. | (ii) | (iv) | (iii) | (i) |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyWhen the circular scale of a screw gauge completes \(2\) rotations, it covers \(1\) mm over the pitch scale. The total number of circular scale divisions is \(50\). The least count of the screw gauge in metres is:
1. \(10^{-4}\)
2. \(10^{-5}\)
3. \(10^{-2}\)
4. \(10^{-3}\)
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyThe determination of the value of acceleration due to gravity \((g)\) by simple pendulum method employs the formula,
\(g=4\pi^2\frac{L}{T^2}\)
The expression for the relative error in the value of \(g\) is:
1. | \(\frac{\Delta g}{g}=\frac{\Delta L}{L}+2\Big(\frac{\Delta T}{T}\Big)\) | 2. | \(\frac{\Delta g}{g}=4\pi^2\Big[\frac{\Delta L}{L}-2\frac{\Delta T}{T}\Big]\) |
3. | \(\frac{\Delta g}{g}=4\pi^2\Big[\frac{\Delta L}{L}+2\frac{\Delta T}{T}\Big]\) | 4. | \(\frac{\Delta g}{g}=\frac{\Delta L}{L}-2\Big(\frac{\Delta T}{T}\Big)\) |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biology