A dielectric slab is inserted between the plates of an isolated charged capacitor. Which of the following quantities will remain the same?

(a) the electric field in the capacitor
(b) the charge on the capacitor
(c) the potential difference between the plates
(d) the stored energy in the capacitor

 
Choose the correct option:
1. (a), (b)
2. (b) only
3. (c), (a)
4. (a), (d)

Subtopic:  Dielectrics in Capacitors |
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The left plate \(A\) of an air capacitor is connected to the positive terminal while the right plate \(B\) is connected to the negative terminal of a cell of voltage \(V_0.\) Assume that the plate area is \(A,\) and the plate separation is \(d.\) If a slab of dielectric constant \(K\) is inserted into the space between the plates, the electric field in the dielectric will be: (compared to the air capacitor)
                      
 
1. more.
2. less.
3. equal.
4. more or less or equal depending on the value of \(K\).
Subtopic:  Dielectrics in Capacitors |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biology